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3 years ago

HELP PLZ I NEED HELP

Mathematics

1 answer:

Crazy boy [7]3 years ago

5 0

For some reason I can’t see the picture sorry

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Circle the statement that are tru as you solve

shepuryov [24]

What statement are you talking about?

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3 years ago

Sandra wants to make gift baskets. She needs 1.3 pounds of flour to make cupcakes and 1.7 pounds of flour to make pies. About ho

Katarina [22]

Answer:

18 pounds of flour

Step-by-step explanation:

Add your wright of flout, 1.3+1.7, getting 3lbs. Then multiply 3 by 6 because thats the number of baskets. Getting 18lbs. of flour

5 0

3 years ago

8y + 4x + 6y=? Plz help

postnew [5]

Answer:

idk, sorry about that one

8 0

3 years ago

Read 2 more answers

Using the given information, give the vertex form equation of each parabola.

Amanda [17]

Answer:

The equation of parabola is given by : $(x-4) = \frac{-1}{3}(y+3)^{2}$

Step-by-step explanation:

Given that vertex and focus of parabola are

Vertex: (4,-3)

Focus:( $\frac{47}{12}$ ,-3)

The general equation of parabola is given by.

$(x-h)^{2} = 4p(y-k)$ , When x-componet of focus and Vertex is same

$(x-h) = 4p(y-k)^{2}$ , When y-componet of focus and Vertex is same

where Vertex: (h,k)

and p is distance between vertex and focus

The distance between two points is given by :

L= $\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}$

For value of p:

p= $\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}$

p= $\sqrt{(4-\frac{47}{12})^{2}+((-3)-(-3))^{2}}$

p= $\sqrt{(\frac{1}{12})^{2}}$

p= $\frac{1}{12}$ and p= $\frac{-1}{12}$

Since, Focus is left side of the vertex,

p= $\frac{-1}{12}$ is required value

Replacing value in general equation of parabola,

Vertex: (h,k)=(4,-3)

p= $\frac{-1}{12}$

$(x-h) = 4p(y-k)^{2}$

$(x-4) = 4(\frac{-1}{12})(y+3)^{2}$

$(x-4) = \frac{-1}{3}(y+3)^{2}$

8 0

3 years ago

If f(x)=x/2-3and g(x)=4x^2+x-4, find (f+g)(x)

Sergeeva-Olga [200]

Step-by-step explanation:

(f+g)(x) = f(x) + g(x)

= x/2-3 + 4x²+x+4

= ..........

4 0

3 years ago