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3 years ago

The school hall is 4 times as long as it is wide. If the perimeter is 55m, what is the length? and what is the width?

1 answer:

6 0

-- The width of the school is ' W '. We don't know what that is yet,
but we're going to find out.

-- We're told that the length is 4 times as much. So the length is ' 4 W '.

-- Perimeter is (2 widths) + (2 lengths).

2 widths = 2 W
2 lengths = 8 W
Perimeter = 10 W

-- We're also told that the perimeter is 55m. That's just what we need.

10 W = 55 m

Divide each side of this equation by 10:

W = 5.5 m

There's the width !
The length of the hall is 4 times as much.

Length = 4 W = 22 m

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1. AB is tangent to circle O at B. The diagram is not drawn to scale. . . circle O. . If AB = 9 and AO = 21.6, what is the lengt

olganol [36]

1) The correct answer is A) 19.6

See the first picture attached.

A line tangent with a circle (AB) forms a 90° angle with the radius drawn from the tangent point (BO). This means that you can apply the Pythagorean theorem:
BO = √(AO² - AB²)
= √(21.6² - 9²)
= √(466.56 - 81)
= √385.56
      = 19.6

2) The correct answer is B) 64

See the second picture attached.

When you have an incircle (a circle inscribed in a triangle), the distances between a vertex and the two nearest tangent points are equal to each other.

This means that:
JA = JB
LA = LC
KC = KB

Therefore the perimeter of ΔJKL will be:
2 × (12 + 15 + 5) = 64

3) The question asks for the measure of arc ZWX
The correct answer is D) 243°

See the third picture attached.

We know that a diameter forms an arc of 180°, because it divides the circle into two equal parts.

Therefore, arc ZRW measures 180°.

In order to find arc ZWX you need to add arc ZRW and arc WX:
ZWX = ZRW + WX
   = 180 + 63
   = 243°

8 0

3 years ago

Read 2 more answers

Which of the following would have the same graphic representation as the function f(x)=16(2)^x

Zinaida [17]

The options 2 and 4 would have the same graphical representation.

Step-by-step explanation:

Step 1:

To determine which functions are equal to the question, we must assign values to x and see which values equal the function f(x) = $16.2^{x}$ .

Any random value can be assigned to x but the same value of x must be assigned to all the equations.

Step 2:

If we substitute x = 5, we get

Question; f(x) = $16.2^{x} = 16.2^{5}= 16.(32) = 512.$

Option 1; f(x) $= 4.4^{x} = 4.4^{5} = 4.(1,024)= 4,096.$

Option 2; f(x) = $4.2^{x+2} = 4.2^{5+2} = 4.(128) = 512.$

Option 3; f(x) = $32^{x} = 32^{5} = 33,554,432.$

Option 4; f(x) $= \frac{1}{4}. 2^{x+6} = \frac{1}{4}. (2^{5+6}) =\frac{1}{4}. (2048) = 512.$

So options 2 and 4 would have the same graphical representation.

6 0

3 years ago

What is the value of x in the equation 2/3

natka813 [3]

Answer:

N/A

Step-by-step explanation:

There is not enough data to answer this question.

6 0

3 years ago

Triangle JKM with side j across from angle J, side k across from angle K, and side m across from angle M

choli [55]

The answer of this question is 883 in

5 0

3 years ago

Arturo invests $2700 in a savings account that pay 9% interest, compounded quarterly. If there are no other transactions, when w

Sedbober [7]

The correct formula for this is as follows:
$A=P(1+\frac{r}{n})^{nt}$
where n is the number of compounding periods per year, and r is the annual interest rate as a decimal,
Plugging the given values into the formula, we get:
$4550=2700(1+\frac{0.09}{4})^{4t}$
This equation can be simplified to:
$1.6852=(1.0225)^{4t}$
Taking logs of both sides gives:
$log 1.6852=4t\times log 1.0225$
which can be rearranged to get:
$t=\frac{log 1.6852}{4\times log 1.0225}=5.864$
So it will take about 5.864 years for the amount to reach $4550.

5 0

3 years ago