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MrRa [10]
3 years ago
7

It's 16inches tall and the exact model is 40 feet long

Mathematics
1 answer:
OleMash [197]3 years ago
4 0
Ahh... this is pretty easy!!
.
Locomotive is 40 feet.
.
Model is 16.
.
So?
.
Divide 40 by 16!!
.
What's that?
.
2.5. 
.
So your answer choice is 2.5
.
Hope I helped!!
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A researcher wants to test to see if husbands are significantly older than their wives. To do this, he collects the ages of husb
OLga [1]

Complete Question

The complete is shown on the first uploaded image

Answer:

The correct option are option 2 and option 4

Step-by-step explanation:

From the question we are told that

   The sample size is  n = 12  

    The test statistics is  t \approx 1.434

    The level of significance is  \alpha = 0.05

    The  rejection region is    t>1.796

   The null hypothesis H_o: \mu_d=0

    The alternative hypothesis is  H_a : \mu_d >0

 From the given values we see that t <  1.796(i.e   1.434 < 1.796 ) which implies that t is not within the rejection region

  Hence we fail to reject the null hypothesis

The conclusion is that there is insufficient evidence to suggest that that the husbands are significantly older than the wife.

4 0
2 years ago
What is a simpler form of the radical expression?<br><br> SOMEONE PLEASE HELP!!
Brilliant_brown [7]

Answer:

Choice B

Step-by-step explanation:

Given radical expression:

\sqrt[4]{1296 {x}^{16}  {y}^{12} }

To Find:

The Simpler form of this expression

Soln:

=  \sqrt[4]{1296 {x}^{16}  {y}^{12} }

We could re-write the given expression, according to the law of exponents:

=  \tt \sqrt[4]{(6x {}^{4}y {}^{3})  {}^{4}  }

Now we need to bring terms out of the radical as:

\tt =   | 6x { }^{4} y {}^{3}  |

Bring out 6x^4 from the absolute & put y^3 only in it:

\tt = 6x {}^{4}  |y {}^{3} |

Choice B is accurate.

7 0
1 year ago
If Anne can type 8 words for every 5 words. James can type if James can type 150 words how many words can Anne type? HELP PLEEEA
erma4kov [3.2K]
So what your saying is that James can type 5 words and Anne can type 8 words right? And James types 150 so how many can Anne type? Is that what your asking?
5 0
2 years ago
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Which are equivalent expressions?
polet [3.4K]

Answer:

Which are equivalent expressions?

Check all that are true.

y + x = 2x

x + x + x + x = 4x (true)

x + x = 2x (true)

x + y + y + x = 2x + 2y (true)

x + y + x + x = 2x + y

Step-by-step explanation:

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3 years ago
What is typically used to quantitatively compare the effectiveness of layouts? A. trial and error B. load-distance model C. expo
Andre45 [30]

Answer:

B. load-distance model

Step-by-step explanation:

A. trial and error

Trial and error is "a fundamental method of problem solving. It is characterised by repeated, varied attempts which are continued until success". But this method is not the best in order to compare effectiveness of layouts

B. load-distance model

The load-distance method is a "mathematical model used to evaluate locations based on proximity factors. The objective is to select a location that minimizes the total weighted loads moving into and out of the facility. The distance between two points is expressed by assigning the points to grid coordinates on a map". And that's the correct option since we are trying to measure the effectiveness of layouts quantitatively.

C. exponential smoothing

This is "a rule of thumb technique for smoothing time series data using the exponential window function". Wheighting observations using the exponential function. But this is a techinique used to smooth s time series not to compare effectiveness of layouts.

D.process control charts

The Control Chart is a "graph used to study how a process changes over time with data plotted in time order". But we don't want to see how the process changes the objective is quantitatively compare the effectiveness of layouts, and this one is not the best option for this.

E. mean absolute deviation (MAD)

The median absolute deviation(MAD) is "a robust measure of how spread out a set of data is. The variance and standard deviation are also measures of spread, but they are more affected by extremely high or extremely low values and non normality". But again is just a measure of spread and not allow to compare effectiveness of layouts.

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