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Naddika [18.5K]
3 years ago
12

Eliminate the parameter. x = t2 + 1, y = t2 - 1

Mathematics
2 answers:
Alexus [3.1K]3 years ago
4 0
\bf \begin{cases}
x=t^2+1\implies x-1=\boxed{t^2}\\
y=t^2-1\\
----------\\
y=\boxed{x-1}-1\\
y=x-2
\end{cases}
GarryVolchara [31]3 years ago
4 0

Answer:

x - y = 2

Step-by-step explanation:

The given equations are x = t² + 1 and y = t² - 1

We have to eliminate the parameter t from these equations.

Since x = t² + 1

t² = x - 1

and y = t² + 1

t² = y - 1

Now we equate both the equations

x - 1 = y - 1

x - y = 1 + 1

x - y = 2

Therefore, answer is x - y = 2

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Answer:

CA=P+2Q

Step-by-step explanation:

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2 years ago
Draw a number line -5 through 5 and mark 2x<6
inna [77]

Answer:

x < 3

Step-by-step explanation:

Before number line can be drawn, there is need to find the value of x in the inequality given. Thus,

2x < 6

Divide both sides by 2

\frac{2x}{2}  <  \frac{6}{2}

x < 3

The number line is indicated in the attached picture.

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3 years ago
A police helicopter flying at a height of 85 feet shines a light on a speeding vehicle below. If the angle of depression is 62 d
Naily [24]

Answer: 96 feet i believe

8 0
3 years ago
What does it mean when a boy says u tryna hang out but you can’t cuz you ain’t home but then the next day he says you going to c
krek1111 [17]

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Say your not home!

Step-by-step explanation:

Say your not home,the set a date when yall can meet again!

7 0
3 years ago
Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with
worty [1.4K]

Answer:

z

Step-by-step explanation:

Assuming this complete question:

"Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean \mu =26 kilograms and standard deviation \sigma=4.2 kilograms. Let x be the weight of a fawn in kilograms. Convert the following z interval to a x interval.

X"

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(26,4.2)  

Where \mu=26 and \sigma=4.2

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

We know that the Z scale and the normal distribution are equivalent since the Z scales is a linear transformation of the normal distribution.

We can convert the corresponding z score for x=42.6 like this:

z=\frac{42.6-26}{4.2}=3.95

So then the corresponding z scale would be:

z

7 0
3 years ago
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