Question

18) If the straight line y=m X touches the circle (x - 2)^2 + (y - 6)^2 = 4, then m= ......

Answer 1

Answer:

(8) d. 4/3    (9) a. (X - 4)^2 + (y-4)^2= 25

Step-by-step explanation:

8. CENTER OF CIRCLE: O (2,6)

     radius of circle : r = √4 = 2

if m = 4/3 line: y = 4/3 x

perpendicular distance (d) from center of circle to line y = 4/3 x is

d = |((4/3 x 2) + (-1) x 6)| / √((4/3)² + (-1)²) = |(-10/3)| / √(25/9) = (10/3) / (5/3) = 2

d = r means line touch with circle

9. center of circle is the intersection of the diagonals of rectangle (4,4) and its radius is 5 (illustrated)

the equation of circle: (X - 4)^2 + (y-4)^2= 25