18) If the straight line y=m X touches the circle (x - 2)^2 + (y - 6)^2 = 4, then m= ......
1 answer:
Answer:
(8) d. 4/3 (9) a. (X - 4)^2 + (y-4)^2= 25
Step-by-step explanation:
8. CENTER OF CIRCLE: O (2,6)
radius of circle : r = √4 = 2
if m = 4/3 line: y = 4/3 x
perpendicular distance (d) from center of circle to line y = 4/3 x is
d = |((4/3 x 2) + (-1) x 6)| / √((4/3)² + (-1)²) = |(-10/3)| / √(25/9) = (10/3) / (5/3) = 2
d = r means line touch with circle
9. center of circle is the intersection of the diagonals of rectangle (4,4) and its radius is 5 (illustrated)
the equation of circle: (X - 4)^2 + (y-4)^2= 25
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Answer:
The correct option is D) (5x − 2)(2x − 3).
Step-by-step explanation:
Consider the provided expression.
Where x is time in minutes.
We need to find the appropriate form of the expression that would reveal the time in minutes when the trough is empty.
When the trough is empty the whole expression becomes equal to 0.
Substitute the whole expression equal to 0 and solve for x that will gives us the required expression.
Now consider the provided option.
By comparison the required expression is D) (5x − 2)(2x − 3).
Hence, the correct option is D) (5x − 2)(2x − 3).