3 years ago

The probability of choosing either a girl or a boy is

Mathematics

2 answers:

Reptile [31]3 years ago

7 0

50%. Idk I think. I guess so lol

valina [46]3 years ago

5 0

It depends on the amount

No.of Girls / total no of boys and girls is boy's probabilty
And
No of boys / total no of boys and girls is girl's probabilty

You might be interested in

The linear equation 3x-4y=8 is written in_______.

Tju [1.3M]

Answer:

standard form

Step-by-step explanation:

Ax + By = C ......which is what form this equation is in...is standard form

5 0

2 years ago

Find the median of the following data set - 37,41,46,48,56,59

erastovalidia [21]

Answer:

The median is 47

8 0

2 years ago

Given ΔRST : ΔLMN, which of the following is true<br> 1.

kvasek [131]

I hope this helps you

m (R)=m (L)

m (S)=m (M)

m (T)=m (N)

8 0

3 years ago

Read 2 more answers

Janice needs at least $125 to buy a new bike. She already has $35 and plans to save $10 every week. If w represents the number o

Vilka [71]

Answer:

10w + 35 >= 125

Step-by-step explanation:

She saves $10m per week. That is 10w.

She already has $35, so add 35 to 10w.

10w + 35 >= 125

4 0

2 years ago

Theorem: A line parallel to one side of a triangle divides the other two proportionately.

Elenna [48]

Answer:

Segment BF = 16 is true.

Step-by-step explanation:

Since, DE is parallel to BC, so DE will divide AB and AC proportionally.

Hence,

$\frac{AE}{EC} = \frac{AD}{DB}$

⇒ $\frac{12}{18} = \frac{6}{DB}$

{Since, given that AE = 12, EC = 18 and AD = 6}

⇒ BD = 9.

Again, since, EF is parallel to AB, so EF will divide BC and AC proportionally.

Hence, $\frac{CE}{AE} = \frac{FC}{BF}$

⇒ $\frac{18}{12} = \frac{24}{BF}$

{Since, given that AE = 12, EC = 18 and FC= 24}

⇒ BF = 16.

Therefore, segment BF = 16 is true. (Answer)

3 0

3 years ago