Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.
public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}
So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.
A quick explanation:
We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.
The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.
Time management,they wouldn’t have enough time to read it and they would become more stressed out
Explanation:
These are the advantages of breaking up a single logical message into a number of fixed sized packets.
- When messages are broken into packets it increases the performance and also the reliability of the internet
- if there is an error in a single packet, this error is not going to affect the entire message.
- the efficiency of the communication line in the internet is improved.
- there is a reduction of traffic. Each packet in a single message can be transmitted through different routes.
- It reduces idleness as each packet can send from different program so each program has a service.
Usually when you encounter the problem you see the error code number "0019" for an invalid bank account or routing transit numbers.
Accounting information is the subject to which this is categorized. As soon as the IRS or (Internal Revenue Service) suspects any error, it will deny the return immediately.
Answer:
It can be "ON" or "OFF". So it can store the numbers 1 and 0, but it certainly doesn't have the capacity to store a letter of the alphabet.
Explanation:
