Question

Solve the system using elimination.

Answer 1

The solution is (1,0)

Explanation:

The two equations are $3x+16y=3$ and $3x-16y=3$

We need to solve the equation using elimination method.

Adding the two equations, we get,

$3x+16y=3\\3x-16y=3\\-------\\6x=6$

$x=1$

Thus, the value of x is 1

Substituting $x=1$ in the equation $3x+16y=3$ , we get,

$3(1)+16y=3$

Simplifying, we get,

$16y=3-3$

$16y=0$

   $y=0$

Thus, the value of y is 0.

The solution is (1,0)