Answer:
With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error:
For this problem, we have that:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is
We need a sample size of at least n, in which n is found M = 0.04.
With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.
Answer:
678
2
679
Step-by-step explanation:
Number of people: 5426
Capacity of table: 8
How many tables are full?
- Number of full tables= 5426/8= 678.25 so full part is 678
How many people are sitting at a table that is not full?
- 0.25 table= 8*0.25= 2 people are sitting at a table that is not full
or
How many tables are needed for all 5,426 people?
Answer:
If the two chords are congruent, then they must be equidistant from the centre of the circle.
Ans: D
Answer:
When you solve systems with two variables and therefore two equations, the ... of any variable is 1, which means you can easily solve for it in terms of the other ... In the substitution method, you use one equation to solve for one variable and ... Look for a variable with a coefficient of 1 … that's how you'll know where to begin.
Step-by-step explanation:
