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4vir4ik [10]
3 years ago
14

Which expression is equivalent to 1/2(2n+6 ​

Mathematics
2 answers:
Sati [7]3 years ago
7 0

Answer:

n+3

Step-by-step explanation:

Andrei [34K]3 years ago
4 0

Answer:

n+3

Step-by-step explanation:

1/2(2n+6)= (1/2*2)n+(1/2*6)

1/2(2n+6)=n+3

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0.2x + 0.3y = 0.5 need help plzz​
krok68 [10]

Answer:

y = − 0.  6 x + 1.6

Step-by-step explanation:

Write in slope-intercept form,  

y = m x + b

Note:

  • The decimals (0.6) and (1.6) ARE repeating...

If you need any other form of working it out let me know!

Glad I could help!!

6 0
3 years ago
Can someone help me please
N76 [4]
26/100 or simplified to 13/50
7 0
3 years ago
Alina by several shares of stock at $28 per-share and sells them at $24.50 per-share what is the percent of decrease in the pric
balu736 [363]
Take the absolute value of the difference, then divide it by the original amount
|28 - 24.5| / 28 = 3.5/28 = 0.125..now we multiply that by 100 to get it into a percent 0.125 * 100 = 12.5% <== ur answer
6 0
3 years ago
Read 2 more answers
What is the solution of ?
Tanya [424]

Answer:

of what???????..???..

5 0
3 years ago
The lengths of nails produced in a factory are normally distributed with a mean of 3.34 centimeters and a standard deviation of
Shtirlitz [24]

Answer:

3.47 and 3.21

Step-by-step explanation:

Let us assume the nails length be X

X \sim N(3.34,0.07^2)

Value let separated the top 3% is T and for bottom it would be B

P(X < T)= 0.97

Now converting, we get

P(Z < \frac{T-3.34}{0.07})= 0.97

Based on the normal standard tables, we get

P(Z < 1.881)= 0.97

Now compare these two above equations

\frac{T-3.34}{0.07} = 1.881 \\\\ T = 1.881 \times 0.07 + 3.34 \\\\ = 3.47

So for top 3% it is 3.47

Now for bottom we applied the same method as shown above

P(Z < \frac{B-3.34}{0.07})= 0.03

Based on the normal standard tables, we get

P(Z < -1.881)= 0.03

Now compare these two above equations

\frac{B-3.34}{0.07} = -1.881

= -1.881 \times 0.07 + 3.34 \\\\ = 3.21

hence, for bottom it would be 3.21

7 0
3 years ago
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