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zhenek [66]
3 years ago
12

Need help with any of these questions 5,6,7,8 please please help me again I missed the lesson in class I need to show all my wor

k and explain

Mathematics
1 answer:
PolarNik [594]3 years ago
5 0
I won't give you the answers but to do unit rate you can use proportion an example is below

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Does anyone know how to answer this?
lozanna [386]
The first thing you would do is subtract 10 from 70 then multiply that by 4 the answer to the whole q is 240 calories. Good luck!
4 0
3 years ago
I need help graphing 2x - 6y = 42 I'm just really lazy​
solong [7]

Answer:

We can use slope intercept form to get the points needed. Y= -7+1/3x The points are (0,-7) and (3,-6)

Step-by-step explanation:

Subtract 2x from the left side and place it over to the right side with the 42. Now we have -6y= 42-2x. From here we divide by -6 and we get y= -7+1/3x. We know that are slope is 1/3 which the one is the rise and the 3 is the run. We also know that our y intercept is -7. We plot the points at (0,-7) and (3,-6)

3 0
3 years ago
Letter=number<br> 14.6=e-3.2
barxatty [35]

Answer: e = 17.8

Step-by-step explanation: 14.6 + 3.2

3 0
3 years ago
Read 2 more answers
James put $1000 in a 2-year CD paying 7% interest, compounded monthly.
ruslelena [56]
To find the future value of this investment the formula is
A=p (1+r/k)^kt
A future value?
P present value 1000
R interest rate 0.07
K compounded monthly 12
T time 2 years
A=1,000×(1+0.07÷12)^(12×2)
A=1,149.81
4 0
3 years ago
Read 2 more answers
Hi . I'm kinda stuck on this question . <br>Help please. <br>Workings please​
Gre4nikov [31]

Answer:

\large \boxed{\text{Q31, D. 6.00 F; 32. C. N21.75; Q33. A. 168.00 F}}

Step-by-step explanation:

Your graph is hard to read, so I re-drew it as best I could.

You must first develop an equation relating francs and naira.

The line goes through the origin, so the general equation is

y = kx

One of the points is (40,240).

\begin{array}{rcl}F & = &k \times N\\240 & = &k \times 40\\k & = & \dfrac{240}{40}\\\\k&=&\textbf{6 F/N}\\\end{array}\\\text{The equation is $\large \boxed{\mathtbf{F = 6 N}}$}

Q 31.

\begin{array}{rcl}F & = &6N\\& = & 6 \times 1.00\\& = & \mathbf{6.00}\end{array}\\\text{The equivalent value of N1.00 is $\large \boxed{\textbf{6.00 F}}$}

Q 32.

\begin{array}{rcl}F & = &6N\\130.5& = & 6 N\\N&=& \dfrac{130.5}{6}\\\\& = & \mathbf{21.75}\\\end{array}\\\text{The equivalent value of 130.5 F is $\large \boxed{\textbf{N21.75}}$}

Q 33.

\begin{array}{rcl}F & = &6N\\& = & 6 \times 28.00\\& = & \mathbf{168.00}\end{array}\\\text{An amount of N28.00 is $\large \boxed{\textbf{168.00 F}}$}

6 0
3 years ago
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