Try the following word problem using GRASP strategy

What is the relative frequency of students that studied independently for more than 2 hours to the total number of students that

AlladinOne [14]

This question is incomplete.

The complete question says;

The two-way table shows the number of hours students studied and whether they studied independently or with a study group.

What is the relative frequency of students that studied independently for more than 2 hours to the total number of students that studied independently?

a) 0.4 c) 0.25

b) 0.33 d) 0.11

Table is attached as image

Answer: C (0.25)

The number of students that studied for more than 2 hours as given in the table are 4.

The total number of people that studied independently include those that studied less than 2 hours and those that studied for more than 2 hours.

Those that studied less than 2 hours independently are 12.

Those that studied more than 2 hours independently are 4.

Hence the total number of people that studied independently is 16.

Therefore the relative frequency of students that studied independently for more than 2 hours to the total number of students that studied independently would be = 4/16 = 1/4 = 0.25.

6 0

2 years ago

Customers arrivals at a checkout counter in a department store per hour have a Poisson distribution with parameter λ = 7. Calcul

IgorLugansk [536]

Answer:

(1)14.9% (2) 2.96% (3) 97.04%

Step-by-step explanation:

Formula for Poisson distribution: $P(k) = \frac{\lambda^ke^{-k}}{k!}$ where k is a number of guests coming in at a particular hour period.

(1) We can substitute k = 7 and $\lambda = 7$ into the formula:

$P(k=7) = \frac{7^7e^{-7}}{7!}$

$P(k=7) = \frac{823543*0.000911882}{5040} = 0.149 = 14.9\%$

(2)To calculate the probability of maximum 2 customers, we can add up the probability of 0, 1, and 2 customers coming in at a random hours

$P(k\leq2) = P(k=0)+P(k=1)+P(k=2)$

$P(k\leq2) = \frac{7^0e^{-7}}{0!} + \frac{7^1e^{-7}}{1!} + \frac{7^2e^{-7}}{2!}$

$P(k \leq 2) = \frac{0.000911882}{1} + \frac{7*0.000911882}{1} + \frac{49*0.000911882}{2}$

$P(k\leq2) = 0.000911882+0.006383174+0.022341108 \approx 0.0296=2.96\%$

(3) The probability of having at least 3 customers arriving at a random hour would be the probability of having more than 2 customers, which is the invert of probability of having no more than 2 customers. Therefore:

$P(k\geq 3) = P(k>2) = 1 - P(k\leq2) = 1 - 0.0296 = 0.9704 = 97.04\%$

4 0

2 years ago

Rohan makes $86,534.25 a year. How much will he pay in Social Security and Medicare taxes this year?

matrenka [14]

Answer:

porfavor en español pls para yo poder resolverlo

4 0

2 years ago

Read 2 more answers

Reflect the point (-20,4)

Firdavs [7]

Refrection of (-20, 4) across x-axis gives (-20, 4) = (-20, -4)

Refrection of (-20, 4) across y-axis gives (20, 4)

Refrection of (-20, 4) across y = -x gives (20, -4)

Refrection of (-20, 4) across y = 7 gives (20, 10)

4 0

3 years ago

Charlie runs at a speed of 3 yards per second.about how many miles does Charlie run

crimeas [40]

I think since he runs 3 yards per hour per second their are 60 seconds in a minute so 60 times equals 180 yards per second

5 0

3 years ago