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zubka84 [21]
3 years ago
5

Which expression is equivalent to sin^2x-sin x-2/sin x-2

Mathematics
1 answer:
Arturiano [62]3 years ago
3 0
Post the problem from the paper
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How can you tell when a pattern shows counting on by tens?
Anastaziya [24]
You can tell by using the time tables
6 0
3 years ago
Given P(A)=0.78P(A)=0.78, P(B)=0.65P(B)=0.65 and P(A\cup B)=0.873P(A∪B)=0.873, find the value of P(A\cap B)P(A∩B), rounding to t
Sever21 [200]

Answer:

P(A\ n\ B) = 0.557

Step-by-step explanation:

Given

P(A) = 0.78

P(B) = 0.65

P(A\ u\ B) = 0.873

Required

Determine P(A\ n\ B)

From laws of probability, we have:

P(A\ n\ B) = P(A) + P(B) - P(A\ u\ B)

Substitute in values

P(A\ n\ B) = 0.78 + 0.65 - 0.873

P(A\ n\ B) = 0.557

Hence, P(A\ n\ B)<em> is calculated to be 0.557</em>

8 0
2 years ago
-3=12y-5(2y-7). Solve for y
Yuliya22 [10]
1. distribute the parentheses.
-3=12y-10y+35

2. Move the constants to the other side
-3-35=12y-10y

3. Subtract the terms
-38=2y

4. Divide by 2 to get y by itself
y=-19
4 0
2 years ago
Read 2 more answers
I need helpp plsss:)
kakasveta [241]

Answer:

*read explanation for both questions*

Step-by-step explanation:

So the first one asks <em>”the first number in a pattern is 6, the pattern follows the rule ’</em><em>multiply by 4’ </em><em>“</em>

The question has the answer to it, so each number would be multiplied by 4. So we have the first one which is 6, next we multiply 6 x 4 = 24. Then we multiply 24 x 4 = 96. and finally you multiply 96 x 4 = 384.

That’s the pattern fo the first one

The second one asks <em>“The shapes have been sorted into two groups. explain what attribute was used to sort the shapes.”</em>

<em />

When we’re looking for attributes, look for what they have in common. For me, I see that Group 1 has the smaller versions of the same shapes in Group 2. So that could be the attribute the question is asking for.

3 0
3 years ago
5m - n + 7 - 4m +6n help
makvit [3.9K]

Answer:

m+5n+7

Step-by-step explanation:

5m-n+7-4m+6n

=5m-4m-n+6n+7

=m+5n+7

4 0
3 years ago
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