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Dahasolnce [82]
3 years ago
13

McKenna spends 1 3/4 hours mopping the floors and 3 3/8 hours mowing and weeding the yard. How many hours does she spend on her

chores
Mathematics
1 answer:
quester [9]3 years ago
6 0

McKenna spent 5\frac{1}{8} hours on her chores

Step-by-step explanation:

We have to simply add fractions to find the total time spent on chores by McKenna

So,

Time spent on mopping = t_m = 1\frac{3}{4}

Time spent on mowing and weeding = t_w = 3\frac{3}{8}

So,

Total\ time = t_m+t_w\\= 1\frac{3}{4} + 3\frac{3}{8}\\= \frac{7}{4} + \frac{27}{8}\\= \frac{14+27}{8}\\= \frac{41}{8}\\=5\frac{1}{8}

Hence,

McKenna spent 5\frac{1}{8} hours on her chores

Keywords: Fractions, addition

Learn more about fractions at:

  • brainly.com/question/9998060
  • brainly.com/question/99841

#LearnwithBrainly

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What is the slope of a line that passes through the origin and the point (-2,1)?
Mazyrski [523]

Answer:

<em>The slope would be</em><u><em> -1/2. </em></u>

Step-by-step explanation:

Since, the midpoint of the segment joining the points P (0, -4) and B (8, 0),

<em> = </em><u><em>( 4, -2 ), </em></u>

Now, the slope of the line passes through the origin and the point ( 4, -2) is,

= <u>-1/2</u>

<h3><u>i think thats the answer</u></h3><h2><u> </u><em><u>HOPE IT HELPS YOU THOUGH</u></em></h2>
8 0
3 years ago
A mapping statement is a way of describing a _____ of a figure
mash [69]
The answer is D transformation. 
7 0
3 years ago
At what angle does a diffraction grating produce a second-order maximum for light having a first-order maximum at 20.0 degrees?
hichkok12 [17]

Answer:

At 43.2°.

Step-by-step explanation:

To find the angle we need to use the following equation:

d*sin(\theta) = m\lambda

Where:

d: is the separation of the grating

m: is the order of the maximum

λ: is the wavelength

θ: is the angle              

At the first-order maximum (m=1) at 20.0 degrees we have:

\frac{\lambda}{d} = \frac{sin(\theta)}{m} = \frac{sin(20.0)}{1} = 0.342

Now, to produce a second-order maximum (m=2) the angle must be:

sin(\theta) = \frac{\lambda}{d}*m

\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.    

I hope it helps you!                                                        

6 0
3 years ago
Susan drove at an average speed of 30 miles per hour for the first 30 miles of a trip and then at an average speed of 60 miles p
maxonik [38]

Answer: option B is the correct answer.

Step-by-step explanation:

Susan drove at an average speed of 30 miles per hour for the first 30 miles of a trip.

Time = distance/speed

This means that time spent by Susan in travelling the first 30 miles would be

Time = 30/30 = 1 hour

He travelled at an average speed of 60 miles per hour for the remaining 30 miles of the trip.

Time = 30/60 = 0.5 hours

Total distance travelled is 30 + 30 = 60 miles.

Total time spent = 1 + 0.5 = 1.5 hours

Speed = distance/time

Average speed = 60/1.5 = 40 miles per hour.

7 0
3 years ago
(For this equation any non-integer values should be entered as fractions)
bazaltina [42]
<span> y = 2/7 x - 1/7
slope = 2/7
</span><span>perpendicular  lines, slope is opposite and reciprocal
</span>so slope of new line = -7/2
<span>passes through the point (9,-32)
</span><span>slope-intercept form: y = mx + b
so
b = y - mx
b = -32 - (-7/2)(9)
b = -32 + 63/2
b = -1/2

equation in </span>slope-intercept form:
y = -7/2 x - 1/2
8 0
3 years ago
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