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3 years ago

What is the range of this function ?

Mathematics

1 answer:

VashaNatasha [74]3 years ago

4 0

If we are only using the values in the table, then the answer is D.

This is because the highest value of y is 40 and the lowest is 37.75. So we must know that y is between these two.

However, if we are using this table as a long term model, then C is the correct answer. We know there is 40 to start and it will continue going down until it hits 0.

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What are the solutions of the equation (x−9)2=64?

maksim [4K]

Answer:

17,1

Step-by-step explanation:

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3 years ago

Can someone help me on this please

Anika [276]

Answer:

sin ∅ = 16 /34

cos ∅ = 30 /34

tan ∅ = 16 /30

Step-by-step explanation:

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2 years ago

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kumpel [21]

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3 years ago

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Using the Addition Method, solve for x in the following system of linear equations.

Anna71 [15]

Answer:

x = 0

Step-by-step explanation:

if 2y + x = 4

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it means 2 - 0 = 2

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4 0

2 years ago

Determine the most precise name for ABCD (parallelogram, rhombus, rectangle, or square). Explain how you determined your answer.

Sonja [21]

<h3>Answer: Rhombus</h3>

======================================================

Reason:

Let's find the distance from A to B. This is equivalent to finding the length of segment AB. I'll use the distance formula.

$A = (x_1,y_1) = (3,5) \text{ and } B = (x_2, y_2) = (7,6)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-7)^2 + (5-6)^2}\\\\d = \sqrt{(-4)^2 + (-1)^2}\\\\d = \sqrt{16 + 1}\\\\d = \sqrt{17}\\\\d \approx 4.1231\\\\$

Segment AB is exactly $\sqrt{17}$ units long, which is approximately 4.1231 units.

If you were to repeat similar steps for the other sides (BC, CD and AD) you should find that all four sides are the same length. Because of this fact, we have a rhombus.

-------------------------

Let's see if this rhombus is a square or not. We'll need to see if the adjacent sides are perpendicular. For that we'll need the slope.

Let's find the slope of AB.

$A = (x_1,y_1) = (3,5) \text{ and } B = (x_2,y_2) = (7,6)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{6 - 5}{7 - 3}\\\\m = \frac{1}{4}\\\\$

Segment AB has a slope of 1/4.

Do the same for BC

$B = (x_1,y_1) = (7,6) \text{ and } C = (x_2,y_2) = (6,2)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{2 - 6}{6 - 7}\\\\m = \frac{-4}{-1}\\\\m = 4\\\\$

Unfortunately the two slopes of 1/4 and 4 are not negative reciprocals of one another. One slope has to be negative while the other is positive, if we wanted perpendicular lines. Also recall that perpendicular slopes must multiply to -1.

We don't have perpendicular lines, so the interior angles are not 90 degrees each.

Therefore, this figure is not a rectangle and by extension it's not a square either.

The best description for this figure is a <u>rhombus</u>.

4 0

1 year ago

Read 2 more answers