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frez [133]
3 years ago
11

Jay and David are Calculating their combined height Jay is 5 3/4 feet tall, and David is 6 1/8 feet tall. What is jay and David'

s combined height?
Mathematics
1 answer:
Murrr4er [49]3 years ago
6 0

Answer: \dfrac{95}{8}\ ft

Step-by-step explanation:

Given

The height of Jay is 5\frac{3}{4}\ ft

The height of David is 6\frac{1}{8}\ ft

Converting mixed to fraction and add the two heights for combined height

\Rightarrow \dfrac{5\times 4+3}{4}+\dfrac{6\times 8+1}{8}\\\\\Rightarrow \dfrac{23}{4}+\dfrac{49}{8}\\\\\Rightarrow \dfrac{46}{8}+\dfrac{49}{8}\\\\\Rightarrow \dfrac{46+49}{8}=\dfrac{95}{8}\ ft

Thus, the combined height of the two is \frac{95}{8}\ ft

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Evaluate the integral of the quantity x divided by the quantity x to the fourth plus sixteen, dx . (2 points) one eighth times t
Anika [276]

Answer:

\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c

Step-by-step explanation:

Given

\int\limits {\frac{x}{x^4 + 16}} \, dx

Required

Solve

Let

u = \frac{x^2}{4}

Differentiate

du = 2 * \frac{x^{2-1}}{4}\ dx

du = 2 * \frac{x}{4}\ dx

du = \frac{x}{2}\ dx

Make dx the subject

dx = \frac{2}{x}\ du

The given integral becomes:

\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{x}{x^4 + 16}} \, * \frac{2}{x}\ du

\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{1}{x^4 + 16}} \, * \frac{2}{1}\ du

\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du

Recall that: u = \frac{x^2}{4}

Make x^2 the subject

x^2= 4u

Square both sides

x^4= (4u)^2

x^4= 16u^2

Substitute 16u^2 for x^4 in \int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du

\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16u^2 + 16}} \,\ du

Simplify

\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16}* \frac{1}{8u^2 + 8}} \,\ du

\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{2}{16}\int\limits {\frac{1}{u^2 + 1}} \,\ du

\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du

In standard integration

\int\limits {\frac{1}{u^2 + 1}} \,\ du = arctan(u)

So, the expression becomes:

\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du

\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(u)

Recall that: u = \frac{x^2}{4}

\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c

4 0
2 years ago
How many distinguishable 11 letter​ "words" can be formed using the letters in MISSISSIPPI​?
SCORPION-xisa [38]
This is given by the multinomial coefficient:

\dbinom{11}{1,4,4,2}=\dfrac{11!}{1!4!4!2!}=34650

If you're not familiar with the multinomial coefficient, you may be able to see it more clearly if you count the number of possible combinations taking each distinct letter n times, where n is the number of times it shows up in the original word.

\underbrace{\dbinom{11}1}_{\text{M}}\underbrace{\dbinom{10}4}_{\text{I}}\underbrace{\dbinom64}_{\text{S}}\underbrace{\dbinom22}_{\text{P}}=\dfrac{11!}{1!10!}\dfrac{10!}{4!6!}\dfrac{6!}{4!2!}\dfrac{2!}{2!0!}=\dfrac{11!}{1!4!4!2!}
4 0
3 years ago
find the volume of a solid that is generated by rotating around the indicated axis the plane region bounded by the giveb curves:
Fofino [41]
Assuming the area below the line y=0 (i.e. x>1) does NOT count, the area to be rotated is shown in the graph attached.

A. Again, using Pappus's theorem,
Area, A = (2/3)*1*(1-(-1))=4/3  (2/3 of the enclosing rectangle, or you can integrate)
Distance of centroid from axis of rotation, R = (2-0) = 2
Volume = 2 π RA = 2 π 2 * 4/3 = 16 π / 3 (approximately = 16.76 units)

B. By integration, using the washer method
Volume = 2\pi\int_{-1}^1(1-x^2)(2-x)dx
=2\pi\int_{-1}^1(x^3-2x^2-x+2)dx
=2\pi[x^4/4-2x^3/3-x^2/2+2x]_{-1}^{1}
=2\pi([1/4-2/3-1/2+2]-[1/4+2/3-1/2-2])
=2\pi(8/3)
= 16 π /3   as before



3 0
3 years ago
15 points with easy explanation please​
GaryK [48]

Answer:

that would be 38 degrees

Step-by-step explanation:

7 0
3 years ago
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Find 3 fractions between 2/8 and 3/8
Illusion [34]

5/16 multiply the denominator by 2 and add 1 to the numerator

9/32 multiply the denominator by 4 and add 1 to the numerator

10/32 multiply the denominator by 4 and add 2 to the numerator

5 0
3 years ago
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