Answer:
8 minutes if Jane was assumed to be stationary
Step-by-step explanation:
The question is on relative speed
First find the distance covered by Jane when Sally left school
Speed=Distance/Time ⇒⇒ Distance=Time×Speed
Time=10minute=10/60 hrs
Jane's speed= 12mph
Distance covered by Jane when Sally left school was= 12 ×10/60 = 2miles
So, when Sally left school, Jane was 2 miles away. To find the time Sally requires to catch up with Jane;
Time=Distance/speed
Time of meeting =2/15 hrs ⇒⇒ 2/15 × 60 =8minutes
Answer:
00000
Step-by-step explanation:
I would say 25 is the answer to it
Answer:
x=-23
Step-by-step explanation:
-3.8x-5.9x=223.1
-9.7x=223.1
x=223.1/-9.7
x=-23
Answer:
9x^4-25x^2+16
Step-by-step explanation:
(x^2−1)(3x−4)(3x+4)=(*)
(x^2−1)((3x)^2−4^2) =
(x^2 - 1)(9x^2-16)=
x^2*9x^2 - x^2*16 - 1*9x^2 +16=
9x^4-16x^2-9x^2+16=
9x^4-25x^2+16
(*) (A-B)(A+B) =A^2 - B^2
