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Artist 52 [7]
3 years ago
13

Mai's younger brother tells her that 10/7 equal to 2‾√ 2 2‾√ 2 . Mai knows this can't be right, because 10/7 is rational and 2‾√

2 2‾√ 2 is irrational. Write an explanation that Mai could use to convince her brother that 10/7 cannot be the square root of 2.
Mathematics
1 answer:
makvit [3.9K]3 years ago
6 0

Answer:

The number 10/7 is a rational number, which means it can be expressed as a fraction. Also, if we divide it would give a decimal infinite periodical number, which means it has a pattern on its decimal numbers.

On the other hand, the square root of 2 is irrational number, that means it can't be expressed as a fraction, because its decimal numbers don't have any pattern at all.

So, Mai's brother can see these type of numbers as crazy (irrational numbers) and sane (rational numbers).

At last, another important characteristic to shows that they aren't equal is that they don't have the exactly decimal numbers.

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Answer:

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Step-by-step explanation:

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(12x + y + z = 26
mel-nik [20]

Option D. D has the matrix of constants [[12], [11], [4]].

Step-by-step explanation:

Step 1:

With the given equations, we can form matrices to represent them.

The coefficients of x, y, and z form a matrix of order 3 ×3, the variables x, y, and z form a matrix of order 1 ×3 and the constants form a matrix of order 1 ×3.

Step 2:

The linear system A is represented as

\left[\begin{array}{ccc}12&1&1\\1&-11&0\\1&-1&4\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}26\\17\\23\end{array}\right].

Step 3:

The linear system B is represented as

\left[\begin{array}{ccc}4&1&1\\1&-11&0\\1&-1&12\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}23\\17\\26\end{array}\right].

Step 4:

The linear system C is represented as

\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}4\\11\\12\end{array}\right].

Step 5:

The linear system D is represented as

\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}12\\11\\4\end{array}\right].

Step 6:

Of the four options, the linear system D has the matrix of constants [[12], [11], [4]]. So the answer is option D. D.

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Inessa05 [86]

answer

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set up equations

average = total points / number of tests

total points = test1 + test2 + test3 + test4+ test5

total points = 88 + 94 +89 + 85 + test5

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plug total points into first eqation and rearrange

average = total points / number of tests

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average * number of tests = 356 + test5

test5 = average * number of tests - 356

plug in values for average and number of tests

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3 years ago
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