Solve the following equation. Round to the nearest tenth. 8

NO LINKS!! Please help me with these notes. Part 1a

erik [133]

Answers:

When we evaluate a logarithm, we are finding the exponent, or power x, that the base b, needs to be raised so that it equals the argument m. The power is also known as the exponent.

$5^2 = 25 \to \log_5(25) = 2$

The value of b must be positive and not equal to 1

The value of m must be positive

If 0 < m < 1, then x < 0

A logarithmic equation is an equation with a variable that includes one or more logarithms.

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Explanation:

Logarithms, or log for short, basically undo what exponents do.

When going from $5^2 = 25$ to $\log_5(25) = 2$ , we have isolated the exponent.

More generally, we have $b^x = m$ turn into $\log_b(m) = x$

When using the change of base formula, notice how

$\log_b(m) = \frac{\log(m)}{\log(b)}$

If b = 1, then log(b) = log(1) = 0, meaning we have a division by zero error. So this is why $b \ne 1$

We need b > 0 as well because the domain of y = log(x) is the set of positive real numbers. So this is why m > 0 also.

5 0

2 years ago

X^2+10x-6=0.........

Georgia [21]

Puting it into the quadrait equation ((-b+-[b^2-4ac]^(1/2)/2a), we get that x= 31^(1/2)-5 or 31^(1/2)+5

4 0

3 years ago

1.) Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth .x squared minus 21 x equals n

Andrew [12]

Part 1
We are given $x^2-21x=-4x$ . This can be rewritten as $x^2-18x=0$ .
Therefore, a=1, b=-18, c=0.
Using the quadratic formula
$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-\left(-18\right)\pm \sqrt{\left(-18\right)^2-4\left(1\right)\left(0\right)}}{2\left(1\right)}$
$x=\frac{18\pm 18}{2}$

The values of x are
$x_1=\frac{18-18}{2}=0$
$x_2=\frac{18+18}{2}=18$

Part 2
Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a quadratic function.

Part 3.
The first equation is $y=x^2+2$ .
The second equation is $y=3x+20$ .

We have
$x^2+2=3x+20$
$x^2-3x-18=0$
Factoring, we have
$\left(x-6\right)\left(x+3\right)=0$
Equating both factors to zero.
$x_1-6=0\rightarrow x_1=6$
$x_2+3=0\rightarrow x_2=-3$

When the value of x is 6, the value of y is
$y=3\left(6\right)+20=38$

When the value of x is -3, the value of y is
$y=3\left(-3\right)+20=11$

Therefore, the solutions are (6,38) or (-3,11)

7 0

2 years ago

)The histogram shows the number of gold medals won by different numbers of students at an art competition. Which of the followin

Mnenie [13.5K]

Answer:

Eight students won 6, 7, or 8 gold medals.

Step-by-step explanation:

We see that the third bin is labelled 6 - 8. Since this is on the horizontal, or x, axis, this means that the students in this "bin" have won 6 - 8 medals, which is the same as saying winning 6, 7, or 8 medals.

Because this "bin" goes to 8, that means that there are 8 students who earned this many medals.

Thus, the answer is D.

Hope this helps!

8 0

2 years ago

Read 2 more answers

In a paragraph, explain whether or not all geometric sequences are exponential functions.

ANTONII [103]

Answer:

In a short terms, if you have geometric sequences are most likely(99% sure) to be exponential functions because aromatic functions are the opposite of exponential. Aromatic function are used for linear equation, graphs, and functions while exponential functions will be used for exponential equations, graphs, and functions. So yes, all geometric sequences are in fact exponential functions.

Hope this is helpful.

8 0

2 years ago

Solve the following equation. Round to the nearest tenth. 8 - 5.4x = 9 + 3.3x