Ask question

Ask question

All categories

3 years ago

9

The slope-intercept form of the equation of a line that passes through point (–3, 8) is y = –2/3x 6. what is the point-slope for

m of the equation for this line?

1 answer:

sleet_krkn [62]3 years ago

6 0

Y-8=-2/3(x+3)

Point slope form

You might be interested in

The area of a parallelogram is 3.36 square feet. the base is 2.8 feet. if the measures of the base and height are each doubled,

kolbaska11 [484]

A =bh

Plug in values and solve for height (h).
A=3.36
b=2.8

3.36 = 2.8h
/2.8 /2.8
1.2 = h

Base and Height doubled:
b = 2.8
h = 1.2

2(2.8)=5.6
2(1.2)=2.4

Plug in new b and h to area equation given to find area:
5.6(2.4) = 13.44

Resulting parallelogram area = 13.44 ft^2

5 0

3 years ago

In how many ways can 13 students be seated in a row of 13 chairs if David, insists on sitting in the first chair?

Delvig [45]

They can only sit one way because they are still in a row
Or did you mean like how many different ways can they sit?

8 0

3 years ago

Cloud [144]

If you are asking if your work is good,thn yes,you are right

7 0

3 years ago

Derivative of<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B3x%7D%5E%7B2%7D%20-%202x%20-%201%20%7D%7B%20%7Bx%7D%5E%7B2

Anastaziya [24]

Answer:

$\displaystyle \frac{dy}{dx} = \frac{2x + 2}{x^3}$

Step-by-step explanation:

we would like to figure out the derivative of the following:

$\displaystyle \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }$

to do so, let,

$\displaystyle y = \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }$

By simplifying we acquire:

$\displaystyle y = 3 - \frac{2}{x} - \frac{1}{ {x}^{2} }$

use law of exponent which yields:

$\displaystyle y = 3 - 2 {x}^{ - 1} - { {x}^{ - 2} }$

take derivative in both sides:

$\displaystyle \frac{dy}{dx} = \frac{d}{dx} (3 - 2 {x}^{ - 1} - { {x}^{ - 2} } )$

use sum derivation rule which yields:

$\rm\displaystyle \frac{dy}{dx} = \frac{d}{dx} 3 - \frac{d}{dx} 2 {x}^{ - 1} - \frac{d}{dx} {x}^{ - 2}$

By constant derivation we acquire:

$\rm\displaystyle \frac{dy}{dx} = 0 - \frac{d}{dx} 2 {x}^{ - 1} - \frac{d}{dx} {x}^{ - 2}$

use exponent rule of derivation which yields:

$\rm\displaystyle \frac{dy}{dx} = 0 - ( - 2 {x}^{ - 1 -1} ) - ( - 2 {x}^{ - 2 - 1} )$

simplify exponent:

$\rm\displaystyle \frac{dy}{dx} = 0 - ( - 2 {x}^{ -2} ) - ( - 2 {x}^{ - 3} )$

two negatives make positive so,

$\displaystyle \frac{dy}{dx} = 2 {x}^{ -2} + 2 {x}^{ - 3}$

<h3>further simplification if needed:</h3>

by law of exponent we acquire:

$\displaystyle \frac{dy}{dx} = \frac{2 }{x^2}+ \frac{2}{x^3}$

simplify addition:

$\displaystyle \frac{dy}{dx} = \frac{2x + 2}{x^3}$

and we are done!

5 0

3 years ago

What is the answer to question 1

Softa [21]

5.3 repeating is the answer

4 0

3 years ago

Read 2 more answers