The correct answer for this question is this one: <span>(-4, -11)
</span>In order to solve this,
Let k1 = 7/10 = fraction of the first part
Let k2 = 3/10 = fraction of the second part
Then, use solve for x and y
x = (k1(x2) +k2(x1)) / (k1+k2)
y = (k1(y2) +k2(y1)) / (k1+k2)
x = (7/10 * 5 + 3/10 * -25) / (7/10 + 3/10 )
<span>x = -8 / 2
x = -4
y = (7/10 * -25 + 3/10 * 10) / (7/10 + 3/10)
y = -14 + 3
y = -11
Hope this helps answer your question. Have a nice day!</span>
2(4z−2) = 44
Simplify both sides of the equation.
Distribute:
(2)(4z)+(2)(−2) = 44
8z + −4 = 44
8z − 4 = 44
Add 4 to both sides.
8z − 4 + 4 = 44 + 4
8z = 48
Divide both sides by 8
8z/8 48/8
z = 6
Answer:
52
Step-by-step explanation:
Let ‘s’ be the son’s age 12 years ago.
Let ‘f’ be the father’s current age.
4 years ago, the son was:
s-4
So, his father is currently:
3(s-4)
=
3s-12
Therefore:
f = 3s-12
In twelve years, the son will be:
s+12
And the father will be:
f+12
This can also be written as:
3s-12+12 as the fathers younger age would be f = 3s+12
=
3s
So, we know that s+12 is half the fathers current age, meaning the father is currently 2(s+12) which is equivalent to 2s+24. Also, we know that the father is currently 3 times the sons age 12 years ago, so 3s (proven by the calculations we made above). Therefore, 2s+24=3s which means 24=s. We can then substitute this, and we will receive 24+12 = 36
Son’s current age: 36
We then substitute the son’s age 12 years ago into 2s+24 to give us the father’s age.
2(24)+24 = 72
Father’s current age: 72
Answer:
There are 25 students in the class.
Step-by-step explanation:
Let x be the number of students in the class
12% failed and the number of students is 3
x*12% = 3
x*.12 = 3
Divide each side by .12
x * .12 /.12 = 3/.12
x =25
There are 25 students in the class
