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3 years ago

Which situation can be modeled by the inequality 48−10≥8 48 - 10 x ≥ 8 ?

1 answer:

7 0

You have $48 to spend on socks, but you need to save at least $8 to pay for the bus trip home. You plan to spend the rest on socks at $10 each (including tax)

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Hey I need help with this question: 6(x-3)^2-26 = 10

ra1l [238]

Answer:

x = 3 ±sqrt(6)

Step-by-step explanation:

6(x-3)^2-26 = 10

Add 26 to each side

6(x-3)^2-26+26 = 10+26

6(x-3)^2 = 36

Divide by 6

6/6(x-3)^2 = 36/6

(x-3)^2 = 6

Take the square root of each side

sqrt((x-3)^2) = ±sqrt(6)

x-3 = ±sqrt(6)

Add 3 to each side

x-3+3 =3 ±sqrt(6)

x = 3 ±sqrt(6)

7 0

3 years ago

What's the completed table

Bingel [31]

1 =46
6=136
7=154
8=172

7 0

4 years ago

radio gives local weather updates every 18 minutes. the first update is at 2:00pm. you turn the radio on at 5:30pm. how long wil

nekit [7.7K]

Youll have to wait 10 mins

3 0

3 years ago

Read 2 more answers

A market surveyor wishes to know how many energy drinks teenagers drink each week. They want to construct a 85% confidence inter

Gre4nikov [31]

Answer:

$7.3-1.440\frac{1.2}{\sqrt{830}}=7.240$

$7.3+1.440\frac{1.2}{\sqrt{830}}=7.360$

So on this case the 85% confidence interval would be given by (7.2;7.4)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=7.3$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma =1.2$ represent the population standard deviation

n=830 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

Since the Confidence is 0.85 or 85%, the value of $\alpha=0.15$ and $\alpha/2 =0.075$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.075,0,1)".And we see that $z_{\alpha/2}=1.440$