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Scilla [17]
3 years ago
10

Suppose the side lengths are multiplied by 2. Describe the change in the perimeter.

Mathematics
1 answer:
serg [7]3 years ago
3 0

Answer:

The perimeter would then be squared

Step-by-step explanation:

Since each length is being multiplied by 2 the you have 2 of the same perimeters. So you just add them together or square it.

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(3x^3-2x^2+4x-8)-(5x^3+12x^2-3x-4)
n200080 [17]

Answer: -2x^3-14x^2+7x-4

Step-by-step explanation:

(3x^3-2x^2+4x-8)-(5x^3+12x^2-3x-4)

Distribute the negative sign.

(3x^3-2x^2+4x-8)-5x^3-12x^2+3x+4

Remove the other parentheses.

3x^3-2x^2+4x-8-5x^3-12x^2+3x+4

Combine like terms.

-2x^3-14x^2+7x-4

3 0
3 years ago
find the slope of the curve y=x^2-2x-5 at the point P(2,5) by finding the limit of secant slopes through point P
Fynjy0 [20]

The point (2, 5) is not on the curve; probably you meant to say (2, -5)?

Consider an arbitrary point Q on the curve to the right of P, (t,y(t))=(t,t^2-2t-5), where t>2. The slope of the secant line through P and Q is given by the difference quotient,

\dfrac{(t^2-2t-5)-(-5)}{t-2}=\dfrac{t^2-2t}{t-2}=\dfrac{t(t-2)}{t-2}=t

where we are allowed to simplify because t\neq2.

Then the equation of the secant line is

y-(-5)=t(x-2)\implies y=t(x-2)-5

Taking the limit as t\to2, we have

\displaystyle\lim_{t\to2}t(x-2)-5=2(x-2)-5=2x-9

so the slope of the line tangent to the curve at P as slope 2.

- - -

We can verify this with differentiation. Taking the derivative, we get

\dfrac{\mathrm dy}{\mathrm dx}=2x-2

and at x=2, we get a slope of 2(2)-2=2, as expected.

4 0
3 years ago
What is 3(8×4-6) +5920 ÷294
rjkz [21]

Answer:

98.13

Step-by-step explanation:


5 0
3 years ago
Please help with my last question.
Bas_tet [7]

Answer:

x = 8.3

y = 20.3

Step-by-step explanation:

21-\frac{2}{3} = 20\frac{1}{3} or 20.3

9-\frac{2}{3} = 8\frac{1}{3} or 8.3

6 0
3 years ago
What is the estimate height of 129.3
Anika [276]
129 .................
8 0
2 years ago
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