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Keith_Richards [23]
3 years ago
8

Solve the linear system of equations using the linear combination method. {8a−4b=205a−8b=62

Mathematics
1 answer:
Nata [24]3 years ago
6 0

Step 1:

Line up respective variables in column.

8a-4b=20.................(1)

5a-8b=62.................................(2)

Step 2:

We need to multiply first equation with -2 so that the coefficient of b becomes equal and opposite of -8.

8a-4b=20 *2

-16a + 8b=-40 ...................(3)

Step 3:

Add equation (2) and (3)

5a-8b=62

-16a+8b=-40

The b terms will cancel out and we are left with only a terms.

-11a = 22

dividing both sides by -11

a=-2

Step 4:

plug this value of a in equation (1) to find value of b,

8a-4b=20

8(-2)-4b=20

-16-4b=20

b=-9

Answer : a=-2 and b =-9

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Y = 2/3 x -3 y = -3/2 x +2 what statement about the lines are true
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Answer:

The product of the slopes of lines is -1.

i.e. m₁ × m₂ = -1

Thus, the lines are perpendicular.

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

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  • b is the y-intercept

Given the lines

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y = -3/2x +2      --- Line 2

<u>The slope of line 1</u>

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By comparing with the slope-intercept form of the line equation

The slope of line 1 is: m₁ = 2/3

<u>The slope of line 2</u>

y = -3/2x +2      --- Line 2

By comparing with the slope-intercept y = mx+b form of the line equation

The slope of line 2 is: m₂ = -3/2

We know that when two lines are perpendicular, the product of their slopes is -1.

Let us check the product of two slopes m₁ and m₂

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Thus, the product of the slopes of lines is -1.

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