Answer:
B is the correct answer accordingly to your question
3/6 possible out comes for heads and tails
Solve for z:
5 (z + 6) - 2 = 9 z
5 (z + 6) = 5 z + 30:
5 z + 30 - 2 = 9 z
Add like terms. 30 - 2 = 28:
5 z + 28 = 9 z
Subtract 9 z from both sides:
(5 z - 9 z) + 28 = 9 z - 9 z
5 z - 9 z = -4 z:
-4 z + 28 = 9 z - 9 z
9 z - 9 z = 0:
28 - 4 z = 0
Subtract 28 from both sides:
(28 - 28) - 4 z = -28
28 - 28 = 0:
-4 z = -28
Divide both sides of -4 z = -28 by -4:
(-4 z)/(-4) = (-28)/(-4)
(-4)/(-4) = 1:
z = (-28)/(-4)
The gcd of 28 and -4 is 4, so (-28)/(-4) = (-(4×7))/(4 (-1)) = 4/4×(-7)/(-1) = (-7)/(-1):
z = (-7)/(-1)
(-7)/(-1) = (-1)/(-1)×7 = 7:
Answer: z = 7
Answer:
Each shirt cost $12
Step-by-step explanation:
First, we have to interpret this question and turn each to an equation, letting shirts represent the letter s and ties represent the letter t.
6 shirts and 3 ties cost $79.50 would be interpreted to 6s+3t=79.5 ,and 3 shirts and 2 ties cost $41 would be interpreted to 3s+2t=41
Hence we have two equations, and we solve them simultaneously.
6s+3t=79.5 (Equation 1)
3s+2t=41 (Equation 2)
We can either use the substitution method or the elimination method but for the sake of this question, we use the Elimination method.
6s+3t=79.5 (Equation 1)
3s+2t=41 (Equation 2)
We multiply equation 1 by 2 and we multiply equation 2 by 3, I'm prefer to eliminate the
2(6s+3t=79.5)
12s+6t=159 Equation 3
3(3s+2t=41)
9s+6t=123 Equation 4
We subtract equation 4 from equation 3.
12s+6t=159
9s+6t=123
12s-9s=3s
6t-6t=0
159-123=36
We therefore have
3s=36
Divide both sides by 3
s=36/3
s=12
One shirt cost $12
