First we use product rule
y=x^2lnx
dy/dx = x^2 d/dx (lnx) + lnx d/dx (x^2)
dy/dx = x^2 (1/x) + lnx (2x)
dy/dx = x + 2xlnx
now taking second derivative:
d2y/dx2 = 1 + 2[x (1/x) + lnx (1)]
d2y/dx2 = 1 + 2[1+lnx]
1+2+2lnx
3+2lnx is the answer
2 because 3 meters is labor 6 feet and 2 is above 5'9'' so it's kinda understandable
Sub the numbers in
7 + 9(6)
=7 + 54
=61
Answer:
B'(1,4)
Step-by-step explanation:
after reflection in line c....line c is perpendicular bisector of B' and B
find the slope line between trough B and B' its _1 hence slope of the perpendicular bisector should be 1... equation of line c is
