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ddd [48]
3 years ago
7

Casey correctly wrote and solved a system of linear equations by substitution. In his work, he substituted an expression for one

variable and solved for the other. This resulted in the equation 5 = 20. What can Casey conclude?
Mathematics
1 answer:
uysha [10]3 years ago
4 0
The equation is undefiened.
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Which expression is equivalent to (3w−8)−4(2w+3)(3w−8)−4(2w+3)?
kolezko [41]
(3w-8)-4(2w+3)(3w-8)-4(2w+3)
(3w-8)-(8w+12)(3w-8)-4(2w+3)
(3w-8)-(24w-96)-4(2w+3)
(3w-8)-(24w-96)-(8w+12)
(-21w-104)-(8w+12)
-29w-92
So the simplified form of this expression is -29w-92. When you look at the answer choices you have, pick the one that would make equal value with the simplified form of the one you gave here.
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Please answer this sum correctly which is the correct options
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The first one and the second one are the correct sums

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3 years ago
Almost all medical schools require applicants to take the Medical College Admission Test (MCAT). To estimate the mean score of t
jenyasd209 [6]

Answer:

97.92% probability that the mean score of your sample is between 22 and 28

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 25, \sigma = 6.5, n = 25, s = \frac{6.5}{\sqrt{25}} = 1.3

What is the probability that the mean score of your sample is between 22 and 28

This is the pvalue of Z when X = 28 subtracted by the pvalue of Z when X = 22. So

X = 28

Z = \frac{X - \mu}{\sigma}

By the Central Limit theorem

Z = \frac{X - \mu}{s}

Z = \frac{28 - 25}{1.3}

Z = 2.31

Z = 2.31 has a pvalue of 0.9896

X = 22

Z = \frac{X - \mu}{s}

Z = \frac{22 - 25}{1.3}

Z = -2.31

Z = -2.31 has a pvalue of 0.0104

0.9896 - 0.0104 = 0.9792

97.92% probability that the mean score of your sample is between 22 and 28

8 0
3 years ago
Please help can complete this analogy
marishachu [46]
Hi! The answer might be hannukah. Hope this helps and friend me!!!!!!!!!!!!!!
8 0
4 years ago
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Which tempature is the warmest
Mademuasel [1]

Answer:

D.) 21 degrees fahrenheit.

Step-by-step explanation:

From warmest to coldest:

d. 21 degrees

a. 16 degrees

b. -16 degrees

c. -21 degrees

Hope this helps you :  )

4 0
4 years ago
Read 2 more answers
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