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3 years ago

Help=10pts 5,6,7,and 8 plz

Mathematics

2 answers:

Lesechka [4]3 years ago

8 0

Answer:

number 5:4/12

#6: 25/45

#7: 26/44

#8: 52/30

Step-by-step explanation:

Gemiola [76]3 years ago

6 0

Answer:

5) 1/3=x/12

12=3x

3x=12 (divide both sides)

12 divided by 3 = 4

therefore, x = 4

6) 5/9=25/y (cross multiply the numbers)

after cross multiplying you should get: 5y=225

divide both sides to get 45

therefore, y = 45

7) 26/z = 13/22 (cross multiply numbers)

after cross multiplying, you should get: 572=13z (swap the numbers)

after swapping the number, you should get: 13z=572 (divide both sides)

after dividing you should get 44

therefore, z = 44

8) b/30 = 2.6/1.5 (simplify expression)

after simplifying you should get: b/30=26/15 (cross multiply after)

after cross multiplying you should get: 15b = 780 (divide both sides)

after dividing both sides, you should get: 52

therefore, b = 52

Hope this helps:)!

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A professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their class

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Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

Let p = percentage of seniors who skip their classes.

So, Null Hypothesis, $H_0$ : p $\leq$ 2% {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, $H_A$ : p > 2% {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of seniors who skipped their classes = $\frac{77}{2521}$

n = sample of classes = 2521

So, test statistics = $\frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }$

= 3.08

The value of the test statistics is 3.08.

Now at 0.01 significance level, the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical value of z as 2.3263 < 3.08, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that seniors skip more than 2% of their classes.

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It’s a rational number.

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