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Veronika [31]
3 years ago
15

When I was 6 my sister was half my age Now I'm 70 how old is my sister?

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
6 0
She would be 67...always going to be 3 years younger
joja [24]3 years ago
6 0
You were 6, she was 3. You are now 70, she is now 67. The answer is 67.
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Jfuwiuhudiwjoqlkdfjdkhkfhhalp
sleet_krkn [62]

Answer:

What is this question do you need help or you are playing

3 0
3 years ago
#7 Cecilia made a fruit basket for her grandmother. There were 3 bananas and 6 oranges in the basket. What is the ratio of the n
castortr0y [4]
The answer is A.

explanation:

the obvious ratio is 3:6, because there are 3 bananas and 6 oranges. if you simplify 3:6 it’s 1:2.

hope i helped :)
4 0
4 years ago
Read 2 more answers
3
Marianna [84]

The expression into a single logarithm is log[(x)^{10}][(2)^{30}]

Step-by-step explanation:

Let us revise some logarithmic rules

  • log(a)^{n}=nlog(a)
  • log(ab)=log(a)+log(b)
  • nlog(a)+mlog(b)=log[(a)^{n}][(b)^{m}]

∵ 10 log(x) + 5 log(64)

- At first re-write 10 log(x)

∴  10 log(x) = log(x)^{10}

- Then re-write 5 log(64)

∴  5 log(64) = log(64)^{5}

∴ 10 log(x) + 5 log(64) = log(x)^{10} + log(64)^{5}

- Use the 3rd rule above to make it single logarithm

∵ log(x)^{10} + log(64)^{5} = log[(x)^{10}][(64)^{5}]

∴ 10 log(x) + 5 log(64) = log[(x)^{10}][(64)^{5}]

∵ 64 = 2 × 2 × 2 × 2 × 2 × 2

∴ We can write 64 as 2^{6}

∴ (64)^{5}=(2^{6})^{5}

- Multiply the two powers of 2

∴ (64)^{5}=(2)^{30}

∴ 10 log(x) + 5 log(64) = log[(x)^{10}][(2)^{30}]

The expression into a single logarithm is log[(x)^{10}][(2)^{30}]

Learn more:

You can learn more about the logarithmic functions in brainly.com/question/11921476

#LearnwithBrainly

6 0
3 years ago
Pls help will give brainly and please don't pick random
Step2247 [10]

Answer:

1.0738 x 10^-2

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
How can one halfx − 5 = one thirdx + 6 be set up as a system of equations? 2y + x = −10 3y + x = 18 2y + 2x = −10 3y + 3x = 18 2
Doss [256]

Answer:

2y-x= -10

3y-x = 18

Step-by-step explanation:

The correct option is . 2y-x = -10 ,  3y-x = 18

one half x − 5 = 1/2 (x-5)

one third x + 6 = 1/3 *(x+6)

1/2 x-5 = 1/3x+6 =y

y= 1/2x-5

y = 1/3x+6

Now,

y=x/2 -5     equation 1

y = x/3 +6    equation 2

By taking L.C.M of the first equation we get:

y=x/2 -5

y= x-10/2

Now multiply both terms by 2.

2y=x-10

2y-x= -10

Now lets solve second equation:

Take L.C.M of the second equation:

y = x/3 +6

y=x+18/3

Multiply both sides by 3

3y= x+18

3y-x = 18

Therefore the system of equations we get is:

2y-x= -10

3y-x = 18 ....

4 0
3 years ago
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