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kompoz [17]
3 years ago
6

Under the all-events test, in addition to specifying that all events to establish the liability must have occurred, the test als

o provides that the business must be able to determine the amount of the liability with reasonable accuracy.1. True2. False
Business
2 answers:
IgorC [24]3 years ago
8 0

Answer:

TRUE

Explanation:

It is true that under the all-events test, in addition to specifying that all events to establish the liability must have occurred, the test also provides that the business must be able to determine the amount of the liability with reasonable accuracy

Under Sec. 461(h), a three-prongall-events test is met when

(1) all events have occurred that establish the fact of the liability;

(2) <u>the amount of the liability can be determined with reasonable accuracy</u>; and

(3) economic performance has occurred.

Arte-miy333 [17]3 years ago
7 0

Answer:

True

Explanation:

An All-Events test a test under U.S. federal income tax law that states all events fixing an accrual-method, taxpayer's right to receive income, or incur expense must occur before the taxpayer can report an item of income or expense. An all-events test is said to be met when :

(1) All events have occurred that fix the fact of liability; and

(2) The liability can be determined with reasonable accuracy.

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3 years ago
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Vlada [557]

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6 0
3 years ago
The parts of an organization's infrastructure, human resources, technology, and procurement that make the delivery of the firm's
alexdok [17]

Answer:

support

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7 0
3 years ago
You're the account manager for a client who wants to increase reservations at her boutique hotel. You've been manually managing
Bumek [7]

Answer:<u><em> Apply target cost-per-acquisition (CPA) bidding to drive conversions at her desired CPA.</em></u>

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3 0
3 years ago
Data were collected on the amount spent by 64 customers for lunch at a major Houston restaurant. These data are contained in the
Naddik [55]

Answer:

a) ME= 1.93

b) confidence interval= (19.59,23.45)

Explanation:

a) Sample of customers is 64, population standard deviation is 6 and confidence level is 99%

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Sample size= 64

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b) Confidence interval

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99% confidence interval is (19.59, 23.45) from the output.

ME= \frac{23.45-19.59}{2}= 1.93

5 0
3 years ago
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