Answer:
an = 1/4(8)^n-1
Step-by-step explanation:
Given the following in a geometric sequence, a2=2, a3=16, and a4=128.
nth term of a sequence = ar^n-1
a is the first term
r is the common ratio
r = a3/a2 = a4/a3
r = 16/2 = 128/16
r = 8
a2 = ar
2 = 8a
a = 2/8
a = 1/4
The nth term by substituting the parameters will be;
an = 1/4(8)^n-1
Don’t have that much money buddy
Answer: -7b² + 2b - 8
Step-by-step explanation:
<u>Given expression</u>
3 - b (7b + 2) + 3b - (11 - b)
<u>Expand parentheses and apply the distributive property if necessary</u>
=3 - b · 7b - b · 2 + 3b - 11 + b
=3 - 7b² - 2b + 3b - 11 + b
<u>Combine like terms</u>
=-7b² + (3b - 2b + b) + (3 - 11)
=
Hope this helps!! :)
Please let me know if you have any questions
<span>(15/4)*z + 12?... I tried working with different ways on the calculator to get the answer and that might be it.</span>