All categories

3 years ago

What is this ?? Pls help

Mathematics

1 answer:

AleksandrR [38]3 years ago

5 0

The answer is 1/y^13

You might be interested in

A) Find a particular solution to y" + 2y = e^3 + x^3. b) Find the general solution.

Reptile [31]

Answer:

a.P.I= $\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)$

b.G.S= $C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x}$

Step-by-step explanation:

We are given that a linear differential equation

$y''+2y=e^{3x}+x^3$

We have to find the particular solution

P.I= $\frac{e^{3x}}{D^2+2}+\frac{x^3}{D^2+2}$

P.I= $\frac{e^{3x}}{3^2+2}+\frac{1}{2} x^3(1+\frac{D^2}{2})^{-2}$

P.I= $\frac{e^{3x}}{11}+\frac{1-2\frac{D^2}{4}+3\frac{D^4}{16}+...}{2}x^3$

P.I= $\frac{e^{3x}}{11}+\frac{x^3-2\frac{\cdot3\cdot 2x}{4}}{2}+0}$ (higher order terms can be neglected

P.I= $\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)$

b.Characteristics equation

$D^2+2=0$

$D=\pm\sqrt2 i$

C.F= $C_1cos \sqrt2x+C_2 sin\sqrt2 x$

G.S=C.F+P.I

G.S= $C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x)$

3 0

3 years ago

A rectangular park is 85 yards wide and 120 yards long.

ki77a [65]

Answer:

A=10506.25 Sq.yards

Step-by-step explanation:

Width of the park=85 yds

Lenght of the park=120 yds

Now,

A=L*W

A=120*85

A=10200 square yards. This is the area of your given rectangle.

Now,

P=2(L+W)

P=2(120+85)

P=2(205)

P=410 this is the perimeter of your given rectangle.

Now,

a=410/4=102.5

Now,calculate the area of newly given distance of each side:

A=a^2

A=102.5^2

A=10506.25 Sq. Yards

This is the new area and is larger than the area of the given rectangle which was 10200 square yards.

3 0

3 years ago

The length of a page in a yearbook is 7 inches. The top margin is 1/2 inch, and the bottom margin in 3/4 inch. What is the lengt

Andrei [34K]

Can you be more specific?

7 0

3 years ago

Select the correct answer

Alecsey [184]

Answer:

1/25x

Step-by-step explanation:

3 0

2 years ago

find the number of running and passing plays using substitution method 110 plays 3 yards per run 7 yards per pass total yards 37

Zinaida [17]

Let x be the number of running plays

Y be the number of passing plays

Since the total plays is 110

X + y = 110

And total yard is 378

3x + 7y = 378

Using the first equation

X = 110 – y and substitute to the 2nd equation

3(110 – y) + 7y = 378

And solve for y

Y = 12

Substitute to eqution 1

X = 110 – 12 = 98

7 0

3 years ago