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Hoochie [10]
3 years ago
13

A trapezoid has an area of 30m^2. if all of its side lengths are tripled, what will its new area be​

Mathematics
1 answer:
Norma-Jean [14]3 years ago
5 0

Answer:

270

Step-by-step explanation:

Because we do not know what the side lengths are, as long as they multiply to 30m^2, it's fine

For this question, let's just say the base is 5, and the height is 6. If we triple 5, we get 15, and if we triple 6, we get 18. 15*18=270

Now what if, the sides are not 5 and 6. Will the area still be the same? Let's find out.

10*3=30 so we can say for this answer, the base is 3, and the height is 10.

10 tripled is 30, and 3 tripled is 9. 30*9=270

So as we look at these 2 answers. we can conclude that the new area, no matter the side lengths, will be 270

Hope this helpes!

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Subtracting this from the numerator gives a remainder of

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and subtracting this from the previous remainder gives a new remainder of

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What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

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Minus and plus sign.

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