All categories

3 years ago

What is the measure of angle RST? Options A) 15° B) 75° C) 105° D) 165°

Mathematics

2 answers:

svet-max [94.6K]3 years ago

7 0

The measurement of angle RST is 105

creativ13 [48]3 years ago

7 0

Answer:

Option C). 105°

Step-by-step explanation:

From the figure we can see a cyclic quadrilateral QRST

<u>To find the measure of <RST</u>

From the figure we can see that, angle RST is an obtuse angle.

The measure of angle RST is nearer to a right angle that is nearer to 90°

From the options we get the measure of angle RST = 105°

You might be interested in

A map of Scotland is drawn to a scale of 1:325,000. How many centimetres on the map would show 65km?

sergejj [24]

Haiii.. i'm from indonesia..
thanks for point:)

5 0

3 years ago

Y=4x-5 what is the slope

Reika [66]

The slope is 4 ok bro bro

7 0

3 years ago

What are the solutions to the quadratic equ ton x2 – 16 = 0?

swat32

Answer:

x=4 and x=-4

Step-by-step explanation:

you dont really have to solve this one when you multiply the answer choices they should equal your B which is -16 and only 4 • -4 = -16 so yeah thats your answer

8 0

3 years ago

Question 9 (1 point)

Romashka [77]

Answer:

Step-by-step explanation:

League A League B

151.12 163.25

148 157

26.83 24.93

29 136

136 145

167 178

207 256

League A in ascending order :

26.83 , 29 , 136, 148 , 151.12 , 167,207

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{26.83+29 +136+ 148+ 151.12+ 167+207}{7}\\\\Mean =123.564$

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=148

Standard deviation= $\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}$ = $=\sqrt{\frac{(26.83-123.564)^2+(29-123.564)^2+.......+(207-123.564)^2}{7}}=63.98$

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 26.83 , 29 , 136, 148

n = 4

Q1=82.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 148 , 151.12 , 167,207

n = 4

Q3=159.06

IQR = Q3-Q1=159.06-82.5=76.56

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

$(82.5-1.5\times 76.56,159.06+1.5\times 76.56)$

(-32.34,273.9)

So, There is no outlier

Maximum = 207

League B in ascending order :

24.93,136,145,157,163.25,178,256

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{24.93+136+145+157+163.25+178+256}{7}\\\\Mean =151.45$

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=157

Standard deviation= $\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}$ = $=\sqrt{\frac{(24.93-151.45)^2+(136-151.45)^2+.......+(256-151.45)^2}{7}}=68.42$

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 24.93,136,145,157

n = 4

$Median = \frac{\frac{n}{2} \text{th term}+(\frac{n}{2}+1) \text{th term}}{2}\\Median = \frac{\frac{4}{2} \text{th term}+(\frac{4}{2}+1) \text{th term}}{2}\\Median = \frac{2 \text{th term}+3 \text{th term}}{2}\\Median = \frac{136+145}{2}=140.5$

Q1=140.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 157,163.25,178,256

n = 4

Q3=170.625

IQR = Q3-Q1=170.625-140.5=30.125

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

$(140.5-1.5\times 30.125,170.625+1.5\times 30.125)$

(95.3125,215.8125)

24.93 and 256 are outliers

Maximum = 256

5 0

3 years ago

ABC is translated 6 units up and 3 units left to create ∆A'B'C'.

aivan3 [116]

B is the right answer for this

6 0

3 years ago