Answer:see explanation
Explanation:
Hello, from your question I see that you need a program which based on countNum's value prints ready then all the numbers to 1 and finally go!, I'd appreciate if you provided information about the numbers after the example you gave as I do not know if they are to be printed too.
The solution I provide includes the countdown to 1 printing newline after each number and text. Try it out!
#include <stdio.h>
int main(void)
{
int countNum;
int i;
countNum = 22;
for ( i = countNum; i > 0; i--) {
if (i == countNum){
printf("Ready!\n");
}
printf("%d\n",i);
}
printf("Go!\n");
return 0;
}
Answer:
The answers are explained below
Explanation:
1) Identify the potential classes in this problem domain be list all the nouns
class Customer
class Acco unt
2) Refine the list to include only the necessary class names for this problem
the class customer is not necessary to solve the problem itself, therefore the only class could be the account class
3) Identify the responsibilities of the class or classes.
The responsibilities of the class account will be
* determination of the type of account--> Acc ount . type(char)
* deposit money into the account --> Acc ount . de posit(float)
* withdraw money into the account --> Acc ount . with draw(float)
* show balance of the account --> Acc ount . bal ance()
* generate interest --> Acc ount . int erest()
Please join the words together. I used spaces due to regulations
Answer:
To query the access database to return a group of records with lastname starting with A, change the LastName field's criteria to A, and then click the run button in the results ribbon group of the design ribbon tab.
Explanation:
Microsoft Access is a database management software used to create, manage, and query a database. Just like a spreadsheet and in relational databases, it stores data in records (rows) and fields (columns). To output the result of a query, the run button in the design ribbon tab is clicked.
I've seen this problem before, you just need the solution to the 'while' loop, right?
Assuming your variable names are the same as the generic question your while loop should look like this:
while (keepGoing != 'n')