Given:
Malik's arts and crafts shop has a bolt of crimson velvet 32 meters long.
Velvet purchased by first customer = 120 centimeters
Velvet purchased by second customer = 14 meters
To find:
The remaining velvet in Malik's shop.
Solution:
We know that,
1 meter = 100 cm
Using this conversion, we get
32 meter = 3200 cm
14 meter = 1400 cm
Now,
Remaining velvet in Malik's shop = (3200 - 120 - 1400) cm
= 1680 cm
Therefore, the remaining velvet in Malik's shop is 1680 cm.
Answer: Yes. The data provides convincing evidence.
Step-by-step explanation:
In a random sample of 40 teenagers, 18 enjoy reading for fun. The percentage of teenagers who enjoy reading for fun will be:
= 18/40 × 100
= 45%
In a random sample of 40 adults, 12 enjoy reading for fun. The percentage of adults who enjoy will be:
= 12/40 × 100
= 30%
Therefore, the proportion of adults who enjoy reading for fun is less than that of teenagers. Therefore, the data provides convincing evidence.
The amount that will be withheld from his paycheck for income tax in all is d. $189.42.
<h3>What is the amount withheld?</h3>
The amount withheld is a credit against the income taxes the employee must pay during the year.
The amount withheld from his paycheck for income tax in all is given by;
Amount withheld = State income tax + ( State income tax× Percentage of federal income tax)
Where:
State income tax=$154.00
Percentage of federal income tax=23%
Substitute all the values in the formula
Amount withheld=$154.00+($154,00×23%)
Amount withheld=$154.00+$35.42
Amount withheld=$189.42
Hence, the amount that will be withheld from his paycheck for income tax in all is d. $189.42.
Learn more about income tax here:
brainly.com/question/25641320
Answer:
Check the attachment as solved.
brainliest please ;)
Answer:
60 kilometers
Step-by-step explanation:
<em>1</em><em> </em><em>centimeter</em><em> </em><em>=</em><em> </em><em>3</em><em> </em><em>kilometers</em><em> </em>
<em>2</em><em>0</em><em> </em><em>×</em><em> </em><em>3</em><em> </em><em>=</em><em> </em><em>6</em><em>0</em><em> </em>