In square $ABCD$, $E$ is the midpoint of $\overline{BC}$, and $F$ is the midpoint of $\overline{CD}$. Let $G$ be the intersectio
n of $\overline{AE}$ and $\overline{BF}$. Prove that $DG = AB$.
       
      
                
     
    
    
    
    
    1 answer:
            
              
              
                
                
Draw DH perpendicular to AE.
By the Side-Angle-Side postulate ΔABE  = ΔBEF.
this is the enitre answer: https://web2.0calc.com/questions/in-square-abcd-e-is-the-midpoint-of-line-bc-and-f-is-the-midpoint-o...
                                
             
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