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wel
3 years ago
7

In square $ABCD$, $E$ is the midpoint of $\overline{BC}$, and $F$ is the midpoint of $\overline{CD}$. Let $G$ be the intersectio

n of $\overline{AE}$ and $\overline{BF}$. Prove that $DG = AB$.
Mathematics
1 answer:
tamaranim1 [39]3 years ago
8 0
Draw DH perpendicular to AE.

By the Side-Angle-Side postulate ΔABE  = ΔBEF.

this is the enitre answer: https://web2.0calc.com/questions/in-square-abcd-e-is-the-midpoint-of-line-bc-and-f-is-the-midpoint-o...

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