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wel
3 years ago
7

In square $ABCD$, $E$ is the midpoint of $\overline{BC}$, and $F$ is the midpoint of $\overline{CD}$. Let $G$ be the intersectio

n of $\overline{AE}$ and $\overline{BF}$. Prove that $DG = AB$.
Mathematics
1 answer:
tamaranim1 [39]3 years ago
8 0
Draw DH perpendicular to AE.

By the Side-Angle-Side postulate ΔABE  = ΔBEF.

this is the enitre answer: https://web2.0calc.com/questions/in-square-abcd-e-is-the-midpoint-of-line-bc-and-f-is-the-midpoint-o...

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2 years ago
A vacuum had been marked down by 20% and solf for $250. What was the original price of the vacuum?
igomit [66]

Answer:

The original price was $312.50

Step-by-step explanation:

If the vacuum was marked down by 20%, that means it was sold for 80% of the full price. It was sold for $250, so 80% of the original price is $250.

Let's set up an equation.

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Divide both sides by 0.8.

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Hope this helps!

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3 years ago
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Here is a riddle:
lilavasa [31]

Answer:

The system of inequalities that represents this situation will be:

f + s < 10

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Step-by-step explanation:

  • Let 'f' represent the first number
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Given that the sum of the two numbers is less than 10. As 'less than' can be represented by '<'.

  • so the inequality would be: f + s < 10

Given that If we subtract the second number from the first, the difference is greater than 3. As 'greater than' can be represented by '>'.

  • so the inequality would be: f-s > 3

Thus, the system of inequalities that represents this situation will be:

f + s < 10

f - s > 3

8 0
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Answer:

A.

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