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3 years ago

How to solve |2x+5|<13

Mathematics

1 answer:

alisha [4.7K]3 years ago

4 0

Answer:

|2x + 5| = 7x

Step-by-step explanation:

I'm not quite sure what you are talking about, but you are wrong. |2x + 5| is < 13. Simply because |2x + 5| = 7x. If you were just counting the 7. But even if you multiply (x = 2, here) 7 * x, you would equal 14. 14 is > 13.

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8. A box is filled with candies in different colors. We have 40 white candies, 24 green ones, 12

Darya [45]

Answer:

$P(Green\ or\ Red) = 0.30$

Step-by-step explanation:

Given

$White = 40$

$Green = 24$

$Red = 12$

$Yellow = 24$

$Blue = 20$

Required

$P(Green\ or\ Red)$

The total numbe of candy is:

$Total = 40 + 24 + 12 + 24 + 20$

$Total = 120$

This probability is calculated as:

$P(Green\ or\ Red) = P(Green) + P(Red)$

For each, we have:

$P(Green\ or\ Red) = \frac{Green}{Total} + \frac{Red}{Total}$

Take LCM

$P(Green\ or\ Red) = \frac{Green+Red}{Total}$

$P(Green\ or\ Red) = \frac{24+12}{120}$

$P(Green\ or\ Red) = \frac{36}{120}$

$P(Green\ or\ Red) = 0.30$

8 0

3 years ago

Hello I don’t understand question 9 a and b. Please show working out.<br> Thanks

brilliants [131]

A) I would make the positive integer x and then form an equation.

x + 30 = x^2 - 12
x + 42 = x^2
0 = x^2 - x - 42 this can be factorised
(x - 7) ( x + 6) Therefore x = 7 or x = -6

Since the question asks for a positive integer the answer is 7.

B) two positive numbers x and y.

X - y = 3
x^2 + y^2 = 117

Use these simultaneous equations to figure out each number.

Rearrange the first equation

x = y + 3

Then substitute it into the second equation.

(y+3)^2 + y^2 = 117
y^2 + 6y + 9 + y^2 = 117
2y^2 + 6y - 108 = 0
then factorise this.
(2y - 12) (y + 9)

This means that y = 6 or y = -9 but it’s 6 because that’s the only positive number.

Use y to find x

x = y + 3
x = 6 + 3
x = 9

So the answers are x = 9 and y = 6.

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3 years ago

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scoundrel [369]

15 x 4 = 60
Hope this helps!

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4 years ago

HELP ASAP HELP PLEASE ASAP

Gnesinka [82]

Answer:

WXYZ can not be a rectangle because consecutive sides are not perpendicular to each other.

Step-by-step explanation:

The given vertices are W(-4,3), X(1,5), Y(3,1) and Z(-2,-1).

Plot these points on coordinate plane and draw the quadrilateral as shown below.

$Slope=\dfrac{y_2-y_1}{x_2-x_1}$

Using this formula, we get

$m_{WX}=\dfrac{5-3}{1-(-4)}=\dfrac{2}{5}$

$m_{XY}=\dfrac{1-5}{3-1}=\dfrac{-4}{2}=-2$

Now,

$m_{WX}\times =\dfrac{2}{5}\times (-2)=-\dfrac{4}{5}\neq -1$

Here, WX and XY are two consecutive sides of quadrilateral but the product of their slopes is not equal to -1. It means they are not perpendicular to each other.

Since, all interior angles of a rectangle are right angles, therefore, WXYZ can not be a rectangle.

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Rzqust [24]

Answer:

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3 years ago