A rhombus has four equal sides. If the perimeter of this rhombus is 164, then the length of one side is 164/4, or 41.
Draw this rhombus. Label all four sides with "41." Label the longer diagonal 80 and the half length of that diagonal 40. You will see inside the rhombus four congruent triangles with hypotenuse 41, leg 10 and unknown height. Thus, this unknown height is found by solving x^2 + 40^2 = 41^2, and x^2=9, so that the length of the shorter diagonal is 2(2) = 18 (answer).
Well, there is nothing following, but if there is anything about K equal to or greater 4, or K being>2 than thats it.
Angle mes BCD = (mes Arc AE-mes ARC BD)/2
Plug: mes BCD = (64+20)/2 = 44° (Number C)
A it’s only right they is no way you can get more then A and it’s rounded
