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chubhunter [2.5K]
3 years ago
15

Help! Geometry question.

Mathematics
1 answer:
valentinak56 [21]3 years ago
6 0

Start with congruencies of 130°:

∠1 and 130° are vertical angles

∠2 and 130° are corresponding angles

∠5 and 130° are alternate exterior angles

m∠1 = m∠2 = m∠5 = 130°

∠7 and 130° are supplementary angles (which means their sum is 180°). So, ∠7 = 50°

Next, find congruencies of ∠7:

∠3 and ∠7 are vertical angles

∠4 and ∠7 are corresponding angles

∠6 and ∠7 are alternate exterior angles

m∠3 = m∠4 = m∠6 = m∠7 = 50°

Answer: B



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The diagram shows the cross-section of a wall of a cinema. It has to be painted. Work out the area that needs to be painted.
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Area = 370 m²

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Step-by-step explanation:

Area of the wall of a cinema hall = Area of a trapezoid (1)+ Area of a rectangle (2) + Area of a trapezoid (3)

Area of a trapezoid = \frac{1}{2}(b_1+b_2)h

where b_1 and b_2 are the parallel sides and h is the distance between these sides.

Area of trapezoid (1) = \frac{1}{2}(11+12)\times 6

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Area of the rectangle (2) = Length × Width

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Area of the trapezoid (3) = \frac{1}{2}(12+10)\times 11

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Now area of the wall = 69 + 180 + 121

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= \frac{370}{25}

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Therefore, number of tins to be purchased = 15

Cost to paint the complete wall = 15 × £7

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