Question

Solve each system by substitution 2x + y = 20 and 6x - 5y = 12

Answer 1

$\huge\mathbf{Answer࿐}$

$\underline{ \underline{ \bf{step} - 1}}$

Taking first equation,

• $2x + y = 20$

• $y = 20 - 2x$

$\underline{ \underline{ \bf{step} - 2}}$

plugging the value of y in second equation,

• $6x - 5y = 12$

• $6x - 5(20 - 2x) = 12$

• $6x - 100 + 10x = 12$

• $16x = 12 + 100$

• $x = \dfrac{112}{16}$

• $x = 7$

$\underline{ \underline{ \bf{step} -3}}$

plugging the value of x in first equation,

• $2x + y = 20$

• $(2 \times 7) + y = 20$

• $14 + y = 20$

• $y = 20 - 14$

• $y = 6$

Conclusion :

• $x = 7$
• $y = 6$

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$\mathrm{ \#TeeNForeveR}$