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puteri [66]
3 years ago
6

Graphing Polynomial Functions

Mathematics
1 answer:
sp2606 [1]3 years ago
8 0

Let's assume

'a' , 'b' are zeros

so, we will find total zeros from graph

We can  curve touches x-axis

Let's assume it touches at x=b

so, there would be two zeros at x=b

it also crosses origin

so, another zero is at x=0

it crosses x-axis one more time

Let's assume that zeros at x=a

so, we have got four zeros

x=a,0,b,b

now, we can set up function

f(x)=(x-0)(x-a)(x-b)(x-b)

we can also write as

f(x)=x(x-a)(x-b)^2.................Answer

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Step-by-step explanation:

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Solve the following equations for 0 ≤ theta ≤ 360º cosec(2 — 45°) = 2​
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Step-by-step explanation:

here ,

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3 years ago
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If `f(x)=x^2-81` and `g(x)=(x-9)^(-1)(x+9)`, find `g(x)xxf(x)`.
marshall27 [118]

<u>Answer:</u>

g ( x ) * f ( x ) = ( x + 9 ) ^ 2

<u>Step-by-step explanation:</u>

We are given the following two functions and we are to find g(x) * f(x):

f(x)=x2-81

g(x)=(x - 9)^{-1} ( x + 9)

g(x)*f(x)=x^{-81} * \frac{x+9}{x-9}

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g ( x ) * f ( x ) = ( x + 9 ) ( x + 9 )

g ( x ) * f ( x ) =( x + 9 ) ^ 2

3 0
3 years ago
Read 2 more answers
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