The period is equal to 2pi/n, where n is the coefficient of t. In this case pi/2. Therefore the period in this example is 4. Frequency is equal to 1/period. Hence the frequency for this problem is 1/4
Answer:
parallel
Step-by-step explanation:
Answer:
II and II only.
Step-by-step explanation:
The first series converges because the common ratio r is 0.8 (<1).
II diverges as |r| > 1.
III is an alternating series with r = -4 - that is |r| = 4 so it diverges.
( 6 , 2)
in other words :
x = 6 , y = 2
Answer:
35000
Step-by-step explanation: