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alukav5142 [94]
3 years ago
12

Statistics grades: In a statistics class ofstudents, there weremen andwomen. Four of the men and five of the women received an A

in the course. A student is chosen at random from the class.(a) Find the probability that the student is a woman.(b) Find the probability that the student received an A.(c) Find the probability that the student is a woman or received an A.(d) Find the probability that the student did not receive an A.
Mathematics
1 answer:
Tomtit [17]3 years ago
8 0

Answer:

(a) The probability that the student is a woman is \frac{n_{2}}{N}.

(b) The probability that a randomly selected student received an <em>A</em> is \frac{9}{N}.

(c) The probability that a student selected is a woman or received an <em>A</em> is \frac{n_{2}+4}{N}.

(d) The probability that a students selected did not receive an <em>A</em> is \frac{N-9}{N}.

Step-by-step explanation:

Let's assume that there were <em>N</em> students in a class.

Also assume that there are <em>n</em>₁ men and<em> </em><em>n</em>₂ women in the class.

Let's denote M = a student is a man, W = a student is a woman and A = a student received an <em>A</em> in the course.

It is provided that 4 men and 5 women received an <em>A</em> in the course.

The probability that a student is a man and he received an A is,

P(M\cap A)=\frac{4}{N}

The probability that a student is a woman and she received an A is,

P(W\cap A)=\frac{5}{N}

(a)

There are <em>n₂</em> students in the class who are female.

The probability that the student is a woman is,

P(W)=\frac{Number\ of\ women}{Total\ number\ of\ students}=\frac{n_{2}}{N}

(b)

The total number of students who received an <em>A</em> is, 9.

The probability that a randomly selected student received an <em>A</em> is:

P(A)=\frac{Number\ of\ student\ receiving\ an\ A}{Total\ number\ of\ students}=\frac{9}{N}

(c)

The probability that a student selected is a woman or received an <em>A</em> is:

P (W ∪ A) = P (W) + P(A) - P(W ∩ A)

                =\frac{n_{2}}{N}+\frac{9}{N}-\frac{5}{N} \\= \frac{n_{2}+9-5}{N}\\ = \frac{n_{2}+4}{N}

(d)

The probability that a students selected did not receive an <em>A</em> is:

P(A^{c})=1-P(A)\\=1 - \frac{9}{N}\\=\frac{N-9}{N}

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