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suter [353]
3 years ago
13

At the end of a​ party, 3/4 cup of dip is left. Jim divides 4/7 of the leftover dip equally between 2 friends. How much dip does

each friend​ get?
Mathematics
1 answer:
Vesnalui [34]3 years ago
7 0

Answer:

First, we need to find the amount of dip that was divided amount the two friends.

We know that it is 4/7 of the left dip  

therefore:

amount divided among the two friends = (4/7) x (3/4) = 3/7 of the original amount of dip.

This amount is divided among two friends,

therefore:

amount that each friend gets = (3/7) / (2) = 3/14 = 0.2 of the amount of dip

tell me if this is completely wrong because i'm not good at this

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What is the constant ratio formula
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DEFINITION of 'Constant Ratio Plan' Aconstant ratio plan is a strategic asset allocation strategy, or formula, which keeps the aggressive and conservative portions of a portfolio set at a fixedratio.
3 0
3 years ago
Help please!
maks197457 [2]

The two inequalities are :

option B and option C

Explanation:

Daniel moves no more than 30 of his sheep and goats into another field. This means the summation of sheep and goats will be at maximum 30.

that is why it is s+g\leq30

And more than 7 of his animals are sheep means sheep are greater than 7. that is why = s>7


7 0
3 years ago
Helpppppppppp with this question???
irakobra [83]
Pretty sure it’s the second one
3 0
3 years ago
Easy question<br><br> Topic: Volume<br><br> Use the other attachment to help u what formula is it
Lemur [1.5K]

Answer:

see below

Step-by-step explanation:

V = l*w*h for the rectangular  tank

V = 70* 40*40

  =112000 cm^3 = 1mL

The water is 84000

Make this a fraction

84000/112000  = 3/4

The water fills 3/4 of the tank

1-3/4 = 1/4

It is 1/4 from the top

Find the volume of the treasure chest

V = 12*10*8 =960

Tower

V = pi r^2

  3.14 * 10^2 *10

  =3140

Water + chest + tower

84000+960+3140 =88100

This is less than 112000 so the water will not overflow

5 0
3 years ago
Read 2 more answers
A marketing research firm wishes to compare the prices charged by two supermarket chains—Miller’s and Albert’s. The research fir
AVprozaik [17]

Answer:

a) F=\frac{s^2_2}{s^2_1}=\frac{1.84^2}{1.4^2}=1.727 \approx 1.73

b) For this case since we have a two tailed test we have two critical values, and we can find the two values since we need that on each tail the area would be \alpha/2 =0.025, the distribution is the F with 9 df for the numerator and denominator, and we can use the following excel codes to find the critical values:

"=F.INV(0.025,9,9)"

"=F.INV(1-0.025,9,9)"

The two critical values are 0.248 and 4.026, so the rejection zone would be: F>4.026 \cup F since our calculated value is not on the rejection zone we fail to rejec the null hypothesis

Step-by-step explanation:

Data given and notation  

n_1 = 10 represent the sampe size for the Miller's Stores

n_2 =10 represent the sample size for the Albert's stores

\bar X_1 =121.92 represent the sample mean for Miller's store

\bar X_2 =114.81 represent the sample mean for Albert's store

s_1 = 1.4 represent the sample deviation for the Miller's store

s_2 = 1.84 represent the sample deviation for the Albert's stores

s^2_2 = 12.25 represent the sample variance for the utility stocks

\alpha=0.05 represent the significance level provided

Confidence =0.95 or 95%

F test is a statistical test that uses a F Statistic to compare two population variances, with the sample deviations s1 and s2. The F statistic is always positive number since the variance it's always higher than 0. The statistic is given by:

F=\frac{s^2_2}{s^2_1}

Solution to the problem  

System of hypothesis

We want to test if the variation for th two groups is the same, so the system of hypothesis are:

H0: \sigma^2_1 = \sigma^2_2

H1: \sigma^2_1 \new \sigma^2_2

a) Calculate the statistic

Now we can calculate the statistic like this:

F=\frac{s^2_2}{s^2_1}=\frac{1.84^2}{1.4^2}=1.727 \approx 1.73

Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have n_1 -1 =10-1=9 and for the denominator we have n_2 -1 =10-1=9 and the F statistic have 9 degrees of freedom for the numerator and 9 for the denominator. And the P value is given by:

P value

p_v =2*P(F_{9,9}>1.727)=0.428

And we can use the following excel code to find the p value:"=2*(1-F.DIST(1.727,9,9,TRUE))"

b) Critical value

For this case since we have a two tailed test we have two critical values, and we can find the two values since we need that on each tail the area would be \alpha/2 =0.025, the distribution is the F with 9 df for the numerator and denominator, and we can use the following excel codes to find the critical values:

"=F.INV(0.025,9,9)"

"=F.INV(1-0.025,9,9)"

The two critical values are 0.248 and 4.026, so the rejection zone would be: F>4.026 \cup F since our calculated value is not on the rejection zone we fail to rejec the null hypothesis

Since our calcu

Conclusion

Since the p_v > \alpha we have enough evidence to FAIL to reject the null hypothesis. And we can say that we don't have enough evidence to conclude that the two deviations are different at 5% of significance.  

8 0
3 years ago
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