Answer:
I will need 26.4 pounds of the expensive nuts and 1.6 pounds of the cheap nuts.
Step-by-step explanation:
Since I have one type of nut that sells for $ 4.50 / lb and another type of nut that sells for $ 8.00 / lb, and I would like to have 28 lbs of a nut mixture that sells for $ 7.80 / lb, to determine how much of each nut will I need to obtain the desired mixture, the following calculation must be performed:
8 x 0.95 + 4.5 x 0.05 = 7.825
8 x 0.94 + 4.5 x 0.06 = 7.79
0.94 x 28 = 26.32
26.4 x 8 + 1.6 x 4.5 = 218.4
218.4 / 28 = 7.8
Thus, I will need 26.4 pounds of the expensive nuts and 1.6 pounds of the cheap nuts.
Answer:
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1. I feel the need to explain things first before I write the numeric value.
Let x be the total number of students in the school. 25% of this value is given to be 35.
(0.25)x = 35
The value of x is 140. 75% of this value is the answer which is equal to 105.
2. Let y be the alternative schools. With this, the number of charter schools is 2x - 6 which is equal to 52
2x - 6 = 52
The value of x is 29. Therefore, there are 29 charter schools.
Answer:
The correct answer is x = 3 and y = 2.
Step-by-step explanation:
There are many ways to solve systems of equations like this, but I'm going to use substitution. This means taking the value of y given by the second equation and plugging it into the first equation. This is modeled below:
2x - y = 4
2x - (-2x+8) = 4
Now, we can simplify the left side of the equation.
2x + 2x - 8 = 4
4x - 8 = 4
We should add 8 to both sides as the next step.
4x = 12
Now we can divide by 4.
x = 3
To solve for y, we can substitute this value found for x back into either one of our original equations.
y = -2x + 8
y = (-2*3) + 8
y = -6 + 8
y = 2
Therefore, the correct answer is x = 3 and y = 2.
Hope this helps!
