What # divided by what # equals -7

Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.

finlep [7]

Answer:

a) $v = \frac{[L]}{[T]} = LT^{-1}$

b) $a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

c) $\int v dt = s(t) = [L]=L$

d) $\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

e) $\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

$v = \frac{ds}{dt}$

$a= \frac{dv}{dt}$

Part a

If we do the dimensional analysis for v we got:

$v = \frac{[L]}{[T]} = LT^{-1}$

Part b

For the acceleration we can use the result obtained from part a and we got:

$a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

Part c

From definition if we do the integral of the velocity respect to t we got the position:

$\int v dt = s(t)$

And the dimensional analysis for the position is:

$\int v dt = s(t) = [L]=L$

Part d

The integral for the acceleration respect to the time is the velocity:

$\int a dt = v(t)$

And the dimensional analysis for the position is:

$\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

$\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

7 0

3 years ago

7/8 of 16 = what with work

trapecia [35]

7/8times16/1 gives 112/8, which is 14.
you multiply both numerators over both denominators.

3 0

3 years ago

Read 2 more answers

bob and Cheryl are taking a road trip that is 189.80 miles. Bob drove 3/4 of the total distance.How many miles did Bob drive?

Tom [10]

142.35 miles. Just multiply 189.80 by 3/4 (or .75).

5 0

3 years ago

Information on a packet of seeds claims that 93% of them will germinate. Of the 200 seeds that I planted, only 175 germinated. (

Anvisha [2.4K]

Answer:

We reject H₀

we accept Hₐ seeds in the packet would germinate smaller than 93%

Step-by-step explanation:

Test of proportions

One tail-test (left side)

93 % = 0.93

p₀ = 0,93

1.- Hypothesis

<h3>H₀ ⇒ null hypothesis p₀ = 0.93</h3><h3>Hₐ ⇒ Alternative hypothesis p = 0.875</h3><h3>2.-Confidence interval 95 %</h3><h3>α = 0,05 </h3><h3>and </h3><h3>z(c) = - 1.64</h3><h3>3.- Compute z(s)</h3><h3>z(s) = (p - p₀)/√(p₀*q₀)/n z(s) = (0.875-0.93)/√0.93*0.07)200</h3><h3>z(s) = - 0,055/ √0.0003255</h3><h3>z(s) = - 0.055/ 0.018</h3><h3>z(s) = - 3,06</h3><h3>4.-Compere z(c) and z(s)</h3><h3>z(s) < z(c) -3.06 < -1.64</h3><h3>z(s) is in rejection region, we reject H₀</h3>

5 0

3 years ago

If candler and oteen are 3 1/2 inches apart on the map, what is the actual distance between Candler and oteen in miles

givi [52]

They would be 0.00005524 miles apart because 1 in equals 0.00001578 miles

6 0

3 years ago