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strojnjashka [21]
3 years ago
7

Factor the common factor out of each expression.

Mathematics
1 answer:
makkiz [27]3 years ago
7 0
6x^3+6x^5+12x^4=6x^3 (1+6X^2+2X)= 6X^3 [1+2X(3X+1)]
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What algebraic rule did you use to preform this<br> translation????
Law Incorporation [45]

Answer:

In geometry, a transformation is an operation that moves, flips, or changes a shape (called the preimage) to create a

new shape (called the image). A translation is a type of transformation that moves each point in a figure the same

distance in the same direction. Translations are often referred to as slides. You can describe a translation using words

like "moved up 3 and over 5 to the left" or with notation. There are two types of notation to know.

1. One notation looks like T(3, 5). This notation tells you to add 3 to the x values and add 5 to the y values.

2. The second notation is a mapping rule of the form (x, y) → (x−7, y+5). This notation tells you that the x and

y coordinates are translated to x−7 and y+5.

Step-by-step explanation:

5 0
3 years ago
A B R and P are four points on a circle with centre 0. A O R and C are four points on a different circle. The two circles inters
Slav-nsk [51]

Answer:

x° = ∠OBR = ∠ABC (base angles of a cyclic isosceles trapezoid)

Step-by-step explanation:

APRB form a cyclic trapezoid

∠APO  = x° (Base angle of an isosceles triangle)

∠OPR  = ∠ORP (Base angle of an isosceles triangle)

∠ORB = ∠OBR (Base angle of an isosceles triangle)

∠APO + ∠OPR + ∠OBR = 180° (Sum of opposite angles in a cyclic quadrilateral)

Similarly;

∠ORB + ∠ORP + x°  = 180°

Since ∠APO = x° ∠ORB = ∠OBR and ∠OPR  = ∠ORP we put

We also have;

∠OPR = ∠AOP = ∠BOR (Alternate interior angles of parallel lines)

Hence 2·x° + ∠AOP = 180° (Sum of angles in a triangle) = 2·∠OBR + ∠BOR

Therefore, 2·x° = 2·∠OBR, x° = ∠OBR = ∠ABC.

6 0
3 years ago
What is the sum of the first 30 terms of this arithmetic sequence? 6,13,20,27,34
Galina-37 [17]

Answer:

3135

Step-by-step explanation:

Givens

a1 = 6

Use t4 - t3 to get d

t4 = 27

t3 = 20

Step One

Find a1 and d

a1 = 6

d = t4 - t3

d = 27 - 20

d = 7

Step Two

Find the 30th Term

tn= a1 + (n -1 )*d

t30 = 6 + (30 - 1) * 7

t30 = 6 + 29*7

t30 = 6 + 203

t30 = 209

Step Three

Find the sum using Sum = (a + t30)*n/2

n = 30              given

a1 = 6               given  

t30 = 209         calculated from step 2

Sum = (a1 + t30)*n/2        Substitute

Sum = (6+ 209)*30/2       Combine like terms and divide by 2

sum = 215 * 15                  Multiply

Sum = 3135                      Answer

4 0
3 years ago
Name one real-world objeslct that suggests points​
JulijaS [17]

Answer:

magnets

Step-by-step explanation:

counter

bottle cap

pushpin

microwave button

6 0
3 years ago
A survey of 1,565 households estimated that 72% of the households in a given state owned a television. What is the population? a
Lostsunrise [7]
You need more information
6 0
3 years ago
Read 2 more answers
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