They are equal to each other.
The first task in such exercises is to order the data in ascending order.
201,218, 242, 257, 265, 275, 301.
The algorithm to find the first quartile of a distribution of discrete observations is: If the number of observations is odd;
Exclude the median. Then, the first quartile is the median of the lower half of the observations.
If the number of observations is even, take the median of the lower half of observations immediately.
Here, we have 7 observations. The median is 257 and the observations below it are 201,218,242. The median of this is 218. Thus, 218 is the first quartile. (Similarly, 275 is the 3rd quartile).
3 x 36= 108/4 = 27
27 is the answer
Answer:
x = 59/7, y = -15/7
Step-by-step explanation:
4x= 2y + 38;
2 - 3y=x
We can substitute for x in the first equation since the second equation is solved for x
4(2-3y) = 2y+38
Distribute
8 - 12y = 2y+38
Add 12y to each side
8-12y+12y = 2y+12y+38
8 = 14y+38
Subtract 38 from each side
-30 = 14y
Divide by 14
-30/14 = y
-15/7 = y
Now solve for x
2 - 3y = x
2 - 3*-15/7 = x
2 +45/7 = x
14/7 + 45/7 = x
59/7 =x
Answer:
The country's population for the year 2030 is 368.8 million.
Step-by-step explanation:
The differential equation is:
Integrate the differential equation to determine the equation of P in terms of <em>t</em> as follows:
![\int\limits {\frac{1}{P(600-P)} } \, dP =k\int\limits {1} \, dt \\(\frac{1}{600} )[(\int\limits {\frac{1}{P} } \, dP) - (\int\limits {\frac{}{600-P} } \, dP)]=k\int\limits {1} \, dt\\\ln P-\ln (600-P)=600kt+C\\\ln (\frac{P}{600-P} )=600kt+C\\\frac{P}{600-P} = Ce^{600kt}](https://tex.z-dn.net/?f=%5Cint%5Climits%20%7B%5Cfrac%7B1%7D%7BP%28600-P%29%7D%20%7D%20%5C%2C%20dP%20%3Dk%5Cint%5Climits%20%7B1%7D%20%5C%2C%20dt%20%5C%5C%28%5Cfrac%7B1%7D%7B600%7D%20%29%5B%28%5Cint%5Climits%20%7B%5Cfrac%7B1%7D%7BP%7D%20%7D%20%5C%2C%20dP%29%20-%20%28%5Cint%5Climits%20%7B%5Cfrac%7B%7D%7B600-P%7D%20%7D%20%5C%2C%20dP%29%5D%3Dk%5Cint%5Climits%20%7B1%7D%20%5C%2C%20dt%5C%5C%5Cln%20P-%5Cln%20%28600-P%29%3D600kt%2BC%5C%5C%5Cln%20%28%5Cfrac%7BP%7D%7B600-P%7D%20%29%3D600kt%2BC%5C%5C%5Cfrac%7BP%7D%7B600-P%7D%20%3D%20Ce%5E%7B600kt%7D)
At <em>t</em> = 0 the value of <em>P</em> is 300 million.
Determine the value of constant C as follows:
It is provided that the population growth rate is 1 million per year.
Then for the year 1961, the population is: P (1) = 301
Then 
.
Determine <em>k</em> as follows:
For the year 2030, P (2030) = P (70).
Determine the value of P (70) as follows:
Thus, the country's population for the year 2030 is 368.8 million.
