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bogdanovich [222]
3 years ago
13

A small plane flies at an altitude of 1500 feet. juan looks up at a 75 dgree angle of elevation and sees the plane. 15 seconds l

ater, the plane was visible at 50 dgree angel.
A. How far in feet did the plane travel in those 15 seconds.
Mathematics
1 answer:
ANTONII [103]3 years ago
7 0
1500:75 A:50
So 1500-15 seconds is A
Not sure what else but there’s an equation
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The probability of an adverse reaction to the flu shot is 0.15. Let r be the number of people stuffering a reaction from a flu s
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The height of a ball above the ground in feet is defined by the function h(t) = -16t Squared + 80t +3, where t is the number of
jasenka [17]
Plug in 2 for t.
=> -16*(2^2) +80*2 +3
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6 0
3 years ago
F:[1/2,infinity)—&gt;[3/4,infinity) <br> f(x)=x^2-x+1 <br> find the inverse of f(x);please explain
dexar [7]

Answer:

f^{-1}(x)=\frac{1}{2}+\sqrt{x-\frac{3}{4}}

Step-by-step explanation:

y=x^2-x+1

We want to solve for x.

I'm going to use completing the square.

Subtract 1 on both sides:

y-1=x^2-x

Add (-1/2)^2 on both sides:

y-1+(-1/2)^2=x^2-x+(-1/2)^2

This allows me to write the right hand side as a square.

y-1+1/4=(x-1/2)^2

y-3/4=(x-1/2)^2

Now remember we are solving for x so now we square root both sides:

\pm \sqrt{y-3/4}=x-1/2

The problem said the domain was 1/2 to infinity and the range was 3/4 to infinity.

This is only the right side of the parabola because of the domain restriction. We want x-1/2 to be positive.

That is we want:

\sqrt{y-3/4}=x-1/2

Add 1/2 on both sides:

1/2+\sqrt{y-3/4}=x

The last step is to switch x and y:

1/2+\sqrt{x-3/4}=y

y=1/2+\sqrt{x-3/4}

f^{-1}(x)=1/2+\sqrt{x-3/4}

8 0
3 years ago
Exponet for 13 ·13·13·13
photoshop1234 [79]
The exponent for that would be 13^3.

If the answer is incorrect, then i am sorry.
6 0
4 years ago
Read 2 more answers
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